Yes the triangles are congruent by the HL Theorem
Answer:
TRUE If substituting the test point produces a false solution, we shade on the opposite side of the line.
FALSE Elimination will give you an exact answer to a system of equations.
Step-by-step explanation:
Weird, I thought I already answer this xD
A point P on the line segment GK may be parametrically represented as

t is a real parameter which controls where on the segment P is. t=0 means P=G, t=1 means P=K. We're interested in the t that gives a 3:2 ratio for PG:PK. That's closer to K so t>1/2. t=3/(3+2) = 3/5.

Answer: (26/5, 8)