__x4=12 12÷4 =__ The Number in the blanks represents :

Ian tosses a bone up in the air for his dog, Spot. The height, h, in feet, that Spot is above the ground at the time t seconds a

kirill115 [55]

Answer:

12 feet per second.

Step-by-step explanation:

Please consider the complete question.

Ian tosses a bone up in the air for his dog, Spot. The height, h, in feet, that Spot is above the ground at the time t seconds after she jumps for the bone can be represented $h(t)=-16t^2+20t$ .

What is Spot's average rate of ascent, in feet per second, from the time she jumps into the air to the time she catches the bone at t=1/2?

We will use average rate of change formula to solve our given problem.

$\text{Average rate of change}=\frac{f(b)-f(a)}{b-a}$

$\text{Average rate of change}=\frac{h(\frac{1}{2})-h(0)}{\frac{1}{2}-0}$

$\text{Average rate of change}=\frac{-16\cdot(\frac{1}{2})^2+20\cdot \frac{1}{2}-(-16\cdot(0)^2+20\cdot (0))}{\frac{1}{2}-0}$

$\text{Average rate of change}=\frac{-16\cdot\frac{1}{4}+10-(0)}{\frac{1}{2}}$

$\text{Average rate of change}=\frac{-4+10}{\frac{1}{2}}$

$\text{Average rate of change}=\frac{6}{\frac{1}{2}}$

$\text{Average rate of change}=\frac{2\cdot 6}{1}$

$\text{Average rate of change}=12$

Therefore, Spot's average rate of ascent is 12 feet per second.

3 0

3 years ago

Dairy farmers are aware there is often a linear relationship between the age, in years, of a dairy cow and the amount of milk pr

Jobisdone [24]

Answer:

B. A cow of 5 years is predicted to produce 5.5 more gallons per week.

Step-by-step explanation:

Let $M(a) = 40.8-1.1\cdot a$ , where $a$ is the age of the dairy cow, measured in years, and $M(a)$ is the predicted milk production, measured in gallons per week.

Besides, we consider $a_{1}$ and $a_{2}$ , such that $a_{1}\ne a_{2}$ , we define the difference between predicted milk productions ( $\Delta M$ ) below:

$\Delta M = -1.1\cdot (a_{2}-a_{1})$ (1)

If we know that $a_{1} = 5\,yr$ and $a_{2} = 10\,yr$ , then the difference between predicted milk productions is:

$\Delta M = -1.1\cdot (10-5)$

$\Delta M = -5.5\,\frac{gal}{week}$

That is, a cow of 5 years is predicted to produce 5.5 more gallons per week than a cow of 10 years. Hence, the right answer is B.

6 0

2 years ago

The population of a city has decreased by 38% since it was last measured. If the current population is 27,900, what what the pre

Varvara68 [4.7K]

Answer:

The population of a city has decreased by 38% since it was last measured. If the current population is 27,900 .Previous population of city was 45000.

Solution:

Given that current population of city is 27900.

Also, population of a city has decreased by 38% since it was last measured.

Let assume that population of city when it was last measured = x

Decreased of 38% means x-38% of x . we can write this as,

$=x-\frac{38}{100} \times x$

$=\frac{100 x-38 x}{100}$

$=\frac{62 x}{100}=\frac{31 x}{50}$

So current population is $\frac{31 x}{50}$

Equating above expression to the given value of current population, we get

$\frac{31 x}{50}=27900$

$x=\frac{27900 \times 50}{31}$

x=45000

Hence previous population of city was 45000.

7 0

3 years ago

Given f(x)= 2x²+4x-6 and g(x)=2x-2, find each function

valkas [14]

F(x)= 2x²+4x-6 and g(x)=2x-2, find each function
1. (f/g) (x) = f(x)÷g(x) = (2x²+4x-6)÷(2x-2)
First factor both top and bottom:
(2x-2)(x+3)÷(2x-2) = x+3

2. f(a + 2) = plug (a+2) in anywhere there is an x in f(x)=2x²+4x-6 -->
2(a+2)^2 +4(a+2)-6 = 2(a^2+4a+4)+4a+8-6, now distribute:
2a^2+8a+8+4a+2, combine like terms
2a^2+12a+10

3. g(a/2) = plug (a/2) in anywhere there's an x in g(x)=2x-2:
2(a/2)-2 = a-2

5 0

3 years ago

Explain why 323.202 is least than 323.21 even though 202 is Grater than 21

matrenka [14]

It is less than 324.21, because as you can see, all the numbers are equal until you get to the 0 & 1, and 1 is greater than 0

7 0

3 years ago

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