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Sergeu [11.5K]
3 years ago
6

__x4=12 12÷4 =__ The Number in the blanks represents :

Mathematics
1 answer:
Rama09 [41]3 years ago
3 0
The number in the blanks is 3
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Find the center and radius of this
ipn [44]

\text{Hello there! :)}

Answer:

\boxed{\text{Center at } (7, -4), \text{ Radius of } 7.}

\text{Formula for a circle: }  (x - h)^{2} + (y - k)^{2}  = r^{2}  \text{ Where:}

h = \text{ x-coordinate of center}\\\\k = \text{ y-coordinate of center}\\\\r = \text{ radius}\\\\\text{Therefore:}

\text{In the equation } (x - 7)^{2}  + (y + 4)^{2}  = 49:

h = 7\\\\k = -4\\\\r = \sqrt[]{49} = 7 \\\\\text{So:}

\text{Center at } (7, -4), \text{ Radius of } 7.

3 0
3 years ago
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Help please 6x^2-18
prohojiy [21]

Answer:

6(x^2-3)

Step-by-step explanation:

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3 years ago
Which expression is equivalent to 1/2 x + (-70) - 2 1/4 x - (-2) *
katovenus [111]

Answer:

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Step-by-step explanation:

8 0
3 years ago
The diagonals of a quadrilateral QRST intersect at P(-1,3). QRST has vertices at Q(3,6) and R(-4,5). What must be the coordinate
erica [24]

S = (-5,0)

T = (2,1)

Step-by-step explanation:

Step 1 :

Given

Q = (3,6) and R = (-4,5). P = (-1,3)

Let S be (a,b) and T be (c,d)

The diagonals of a parallelogram bisect each other. so in order to ensure that QRST is a parallelogram, P must be the mid point of the diagonals QS and RT.

Step 2 :

P is the midpoint  of QS

So we have (3+a) ÷ 2 =  -1  and (6 + b) ÷ 2 = 3

=> 3 + a = -2    and 6 + b = 6

=> a = -5  and b =0

So S should be (-5,0)

Step 3 :

P is the midpoint  of RT

So we have (-4+c) ÷ 2 =  -1  and (5 + d) ÷ 2 = 3

=> -4+ c = -2    and 5 + d = 6

=> c = 2  and d =1

So T should be (2,1)

Step 4 :

Answer :

S = (-5,0)

T = (2,1)

6 0
3 years ago
Type the expression that results from the following series of steps:
Sever21 [200]
6-z

Z-6 would be wrong because the question said start with 6
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2 years ago
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