Answer:
The magnitude of the induced voltage in the loop is 20 mV.
Explanation:
given;
length of loop, L = 0.43 m
width of loop,w = 0.43 m
velocity of moved loop, v = 0.15m/s
magnetic field strength,B = 0.31 T
To determine the magnitude of the induced voltage in the loop, we apply Faraday's law;
magnitude induced E.M.F = BLv
magnitude induced E.M.F = 0.31 x 0.43 x 0.15 = 0.02 V = 20 mV
Therefore, the magnitude of the induced voltage in the loop is 20 mV.
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Answer:
This values shows a right angle triangle
Explanation:
Given;
a vector 4.0 km due East
a 3.0 km due north
the resultant vector is 5.0 km
The resultant vector can be obtained by Pythagoras theorem if the vectors form a right angle triangle.
R² = 4² + 3²
R² = 16 + 9
R² = 25
R = √25
R = 5 km (right angle triangle proved)
Therefore, this values shows a right angle triangle
Answer:B
Explanation:
Initial velocity, u=0m/s
Distance,s=20m
a=+g=9.8m/s*s
Using v*v=u*u+2gs
v*v=0+2*9.8*20
v*v=392
v=19.8
When s=20m, v = 19.8m/s
Therefore when v = 10m/s, s= 10*20/19.8
s =10.1m
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