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Ganezh [65]
3 years ago
12

A potato and raisins salad has been warmed up to a temperature of 80∘C80∘C and let it stand for three minutes. Then one tries a

bite.
Would the potatoes and raisins be equally warm? Potatoes have a specific heat of 3430 J/(kg⋅∘C)3430 J/(kg⋅∘C). Raisins have a specific heat of 1630 J/(kg⋅∘C)1630 J/(kg⋅∘C).

a) No. Potatoes will be warmer.

b) No. Raisins will be warmer.

c) Yes
Physics
1 answer:
barxatty [35]3 years ago
6 0

Answer : The correct option is, (a) No. Potatoes will be warmer.

Explanation :

Formula used :

Q=m\times c\times \Delta T

where,

Q = heat taken

m = mass of substance

c = specific heat of substance = ?

\Delta T = change in temperature

As we are given that the potatoes have a specific heat of 3430J/(kg^oC) and raisins have a specific heat of 1630J/(kg^oC). That means higher the value of specific heat the more heat taken by the substance (more warmer will be the substance). So, the potatoes will be more warmer as compared to raisins.

Hence, the correct option is, (a) No. Potatoes will be warmer.

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Answer:

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Under the assumption that streams are formed by incompressible fluids, so that volume flow can observed conservation:

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Dimensionally speaking, we can determine the depth of the resulting stream (h_{3}), in meters, by expanding (1) in this manner:

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v_{1}, v_{2} - Speed of the merging streams, in meters per second.

h_{1}, h_{2} - Depth of the merging streams, in meters.

w_{1}, w_{2} - Width of the merging streams, in meters.

w_{3} - Width of the resulting stream, in meters.

v_{3} - Speed of the resulting stream, in meters per second.

If we know that w_{1} = 8.3\,m, h_{1} = 3.2\,m, v_{1} = 2.2\,\frac{m}{s}, w_{2} = 6.8\,m, h_{2} = 3.2\,m, v_{2} = 2.4\,\frac{m}{s}, w_{3} = 10.4\,m and v_{3} = 2.8\,\frac{m}{s}, then the depth of the resulting stream is:

h_{3} = \frac{(8.3\,m)\cdot (3.2\,m)\cdot \left(2.2\,\frac{m}{s} \right) + (6.8\,m)\cdot (3.2\,m)\cdot \left(2.4\,\frac{m}{s} \right)}{(10.4\,m)\cdot \left(2.8\,\frac{m}{s} \right)}

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