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katen-ka-za [31]
4 years ago
7

What’s the answers????!!!!

Mathematics
1 answer:
Basile [38]4 years ago
6 0

Answer:

f(0) = 1

Step-by-step explanation:

The initial value is the value when x = 0.

f(x) = 4^x

For x = 0,

f(0) = 4^0

f(0) = 1

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Which symbol completes the statement 2/3 ___ 5/8
kondaur [170]
It goes 2/3  1/2 and 5/8 


so the answer is 1/2 or the way I originally got it 3/6

HOPE THIS HELPS!!!!
3 0
3 years ago
If P and Q are two sets then n( P-Q) means ?
Lapatulllka [165]

\huge{\mathbb{ \tt{ANSWER}}}

I shall use the symbol U for union

^ for intersection

~ for complement

<h3 /><h3>----------------------------------------------------------------------------------------------------</h3>

The property of set subtraction states that for any sets X and Y, X-Y = X ^ Y~

That is in words, X throw away Y is the same as the intersection of X and the complement of Y

or X and anything NOT in Y

At the SET level, the proof looks like this:

(P-Q) U (Q-P) = « given

(P^Q~) U (Q ^ P~) = « property of set subtraction

(P U Q) ^ (P U P~) ^ (Q~ U Q) ^ (Q~ U P~) = « distributive property

(P u Q) ^ (Q~ U P~) = « Union of any set with it's complement is the universal

set which gets dropped by any intersection of a non-universal set

(P u Q ) ^ (Q ^ P)~ = « De Morgan's Law

(P u Q) - (Q ^ P) = « property of set subtraction

(P u Q) - (P ^ Q) « commutative property

<h3>----------------------------------------------------------------------------------------------------</h3>

At the ELEMENT level, the proof looks like this:

» Proves left side is subset of right side

If x is in (P-Q) U (Q-P) then x is in (P-Q) OR x is in (Q-P)

If x is in P-Q then x is in P but not in Q.

Then X is in P U Q.

Since x is not in Q, x is NOT in P ^ Q

Hence x is in P U Q but NOT in P^Q, which

means it is an element if (P U Q) - (P ^ Q)

Therefore x is an element of the set defined by the right side, which means (P-Q) U (Q-P) is a subset of (P U Q) - (P ^ Q)

« proves right side is subset of the left side

If x is an element of (P U Q) - (P ^ Q) then

x is in (P U Q) but NOT in (P^Q)

Since x is in P U Q, x is in P OR x is in Q.

Since x is NOT in (P^Q) then x is NOT in BOTH P and Q.

Hence x is in either P or Q but not both.

If x is in P, then x is not in Q, so x is in P-Q.

Therefore x is in (P-Q) U (Q-P).if x is in Q, then x is not in P, so x is in Q-P.Therefore x is in (Q-P) U (P-Q).There x is an element of set defined by the left side, which menas (P u Q)-(P ^Q) is a subset of (P-Q) U (Q-P).

#CarryOnLearning

#LetsEnjoyTheSummer

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chubhunter [2.5K]
C is the answer hope this helps. 
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zalisa [80]
Perimeter of a triangle = all 3 sides added together

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6 0
4 years ago
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