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aksik [14]
3 years ago
13

The manager of a gift store is printing brochures and fliers to advertise sale items. Each brochure cost $0.08 to print, and eac

h flier costs $0.04 to print. A brochure requires 3 pages, a flier requires 2 pages. The manager does not want to use more than 600 pages, and she needs at least 50 brochures and 150 fliers. How many of each should she print to minimize the cost?
a.
45 brochures
200 fliers
c.
50 brochures
150 fliers
b.
50 brochures
200 fliers
d.
80 brochures
175 fliers
Mathematics
2 answers:
Yuliya22 [10]3 years ago
5 0
50 brochures and 150 fliers with a cost of 10$
ad-work [718]3 years ago
3 0

Answer:

Option

C. 50 brochure and 150 fliers  is correct answer if she print 50 brochure and 150 fliers then the cost is minimum.

Step-by-step explanation:

Given

Cost of each brochure= $0.08

Cost of each flier= $0.04

Required pages for one brochure= 3

Required pages for one flier= 2

Total number of pages we can use = Less than or equal to 600

Total number of brochures required= Atleast 50

Total number of fliers required= Atleast 150

She want to minimze cost then she needs total number of  brochures and flies

A. 45 brochures and 200 fliers

<h3> This option is wrong because she required atleast 50 brochures . But in given option total number brochures are 45 . Therefore , it is false.</h3>

B. 50 brochures and 200 fliers

Cost of 50 brochures= 50\times 0.08

Cost of 50 brochures= $4

Cost of 200 fliers=200\times 0.04

Cost of 200 fliesr= $8

<h3> Total cost  for 50 brochures and 200 fliers= 4+8= $12</h3>

C. 50 brochures and 150 fliers

Cost of 50 brochures=50\times0.08

Cost of 50 brochures= $4

Cost of 150 fliers= 150\times0.04

Cost of 150 fliers= $6

<h3>Hence, the total cost for 50 brochures and 150 fliers= 4+6=$10</h3>

D. 80 brochures and 175 fliers

Cost of 80 brochures=80\times 0.08

Cost of 80 brochures=$6.4

Cost of 175 fliers=175\times 0.04

Cost of 175 fliers= $7

<h3>Therefore , the total cost of 80 brochures and 175 fliers = 6.4+7=$13.4</h3>

Therefore , option c is correct option when she need 50 brochures and 150 fliers then the cost is minimum.

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