Answer:
13.2 miles
Step-by-step explanation:
To solve this, we will need to first solve for the base of the triangle and then use the information we find to solve for the shortest route.
(5.5 + 3.5)² + b² = 15²
9² + b² = 15²
81 + b² = 225
b² = 144
b = 12
Now that we know that the base is 12 miles, we can use that and the 5.5 miles in between Adamsburg and Chenoa to find the shortest route (hypotenuse).
5.5² + 12² = c²
30.25 + 144 = c²
174.25 = c²
13.2 ≈ c
Therefore, the shortest route from Chenoa to Robertsville is about 13.2 miles.
Answer:
Step-by-step explanation:So we know x + y = 21 and 5x +10y = 165 We line them up in columns x + y = 21 5x +10y = 165 To eliminate the x variable, I'll multiply every element in the 1st equation by -5. -5x + -5y = -105 5x + 10y = 165 Now we combine (add) the equations, which eliminates x altogether. 5y = 60 ... y = 12 From there, x + 12 = 21 ... x = 21-12 ... x = 9 You should double check. Do 9 nickles and 12 dimes equal $1.65? A very important thing to remember using this method is to do the same thing to each element in the equation that you change! I hope that helps.
Answer:
At least 6 shirts should be brought to avail a total reduction of Rs 40.
Step-by-step explanation:
The marked price of each shirt = Rs 28
Discount offered = 25%
So, 25% of marked price 28 = ![\frac{25}{100} \times 28 = 7](https://tex.z-dn.net/?f=%5Cfrac%7B25%7D%7B100%7D%20%20%5Ctimes%2028%20%3D%207)
⇒Reduction on each shirt is Rs 7
Now, total amount reduction needed = Rs 40
So, number of shirts purchased = ![\frac{\textrm{Total reduction needed}}{\textrm{Reduction on each shirt}}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Ctextrm%7BTotal%20reduction%20needed%7D%7D%7B%5Ctextrm%7BReduction%20on%20each%20shirt%7D%7D)
= 40 Rs /7 Rs = 5. 71 ≈ 6
So, at least 6 shirts should be brought to avail a total reduction of Rs 40.
Answer:
see explanation
Step-by-step explanation:
- 2.3 + (- 5.7)
reminder that + (- ) = -
To obtain - 3.4 it is likely that she added 2.3 to - 5.7
The solution is
- 2.3 - 5.7 = - 8