Solve for the first variable in one of the equations, then substitute the result into the other equation.
Point Form:
x= 1, y= -4
Answer:
The area of the circle is ![36\pi\ units^{2}](https://tex.z-dn.net/?f=36%5Cpi%5C%20units%5E%7B2%7D)
Step-by-step explanation:
we know that
The area of a circle subtends a central angle of
radians
so
By proportion find the area of the circle
![\frac{33\pi }{(11\pi /6)}=\frac{x}{2\pi}\\ \\ x=2\pi*( 33*6)/11\\ \\x=36\pi\ units^{2}](https://tex.z-dn.net/?f=%5Cfrac%7B33%5Cpi%20%7D%7B%2811%5Cpi%20%2F6%29%7D%3D%5Cfrac%7Bx%7D%7B2%5Cpi%7D%5C%5C%20%5C%5C%20x%3D2%5Cpi%2A%28%2033%2A6%29%2F11%5C%5C%20%5C%5Cx%3D36%5Cpi%5C%20units%5E%7B2%7D)
Answer:
1:D
2:A
3:C
4:E
5:B
Step-by-step explanation:
A negative exponent will be when you move the decimal point to the left. A positive exponent will be moving the decimal point to the right.
The number of the exponent is how many times you will move the decimal point.
The formula for standard deviation is in attachment the mean (or average is subtracted from each data sample then squared, then summed up for all data samples, then divided by the number of samples, then finally the square root is taken.
The first row of data will have a standard deviation of 0.
The second row of numbers will have a low standard deviation because the differences between the sample data values are low ( <10).
The third row of number will have a somewhat larger standard because of the spread of the numbers.
The last row will have a slightly smaller standard deviation that the 3rd row because of the zero's
What smaller number can you get other than 0?
The first row of data has a 0 or smallest standard deviation