The predicted value of the car in the year 2006 to the nearest dollar would be $651.
<h3>What is the predicted value of the car?</h3>
The first step is to determine the rate of depreciation
g = (FV/PV)^(1/n) - 1
Where:
FV = value of the car in 2001
PV = value of the car in 1993
n = number ofyears = 8
(2700/26,300)^(1/8) - 1 = -24.76%
Now determine the value of the car in 2006
2700x ( 1 - 0.2476)^5 = $651
To learn more about depreciation, please check: brainly.com/question/25552427
We are tasked to solve for the median of the doctor's patients during the last 7 days that he was on duty. The given numbers are the following:
24, 27, 31, 19, 26, 15 and 19
Solving for the median, we have:
Median = (24 + 27 + 31 + 19 + 26 + 15 + 19) / 7 days
Median = 23
The median is 23.
Answer:
7x² meters
Step-by-step explanation:
Area = length × width
35x³ = length × 5x
length = 7x²
<span> For this case we have an expression of the form:
</span>
![\sqrt[4]{16x^{11}y^8}/(81x^7y^6)](https://tex.z-dn.net/?f=%20%5Csqrt%5B4%5D%7B16x%5E%7B11%7Dy%5E8%7D%2F%2881x%5E7y%5E6%29%20)
To solve the problem, we must rewrite the expression using properties of exponents.
Rewriting the expression we have:
![\sqrt[4]{2^4x^8x^3y^8}/(81x^7y^6)](https://tex.z-dn.net/?f=%20%5Csqrt%5B4%5D%7B2%5E4x%5E8x%5E3y%5E8%7D%2F%2881x%5E7y%5E6%29%20)
Then, by root properties we have:
![2x^2y^2(\sqrt[4]{x^3})/(81x^7y^6) ](https://tex.z-dn.net/?f=%202x%5E2y%5E2%28%5Csqrt%5B4%5D%7Bx%5E3%7D%29%2F%2881x%5E7y%5E6%29%0A)
Then, by power properties again:
![2(\sqrt[4]{x^3})/(81x^5y^4)](https://tex.z-dn.net/?f=%202%28%5Csqrt%5B4%5D%7Bx%5E3%7D%29%2F%2881x%5E5y%5E4%29%20)
Answer:
An <span>expression that is equivalent is:
</span>