6x to the power of 2 - 3x let me know if I’m wrong
First we need to know the actual answer, which would be 14, knowing this, we can split up 84 into smaller pieces that are easier to divide, 42 would be easier, so distributive property would be (42 divided by 6)+(42 divided by 6), 6x7=42, 7x2=14, so yea i hope this helped
No answer
1. 37x+1/2-x-1/4=9(4x-7)-5 * remove parentheses
2. 36x+1/4=9(4x-7)-5 * simply to 36x+1/4
3.36x+1/4=36x-63-5 *expand*
4. 36x+1/4=36x-68 *simply to 36x-68*
5. 1/4 = -68 * cancel both 36x on both sides*
6. 1/4=-68 equals...no solution
Answer:
- determinant: -15
- x = 3; y = 4; z = 1
Step-by-step explanation:
The matrix of coefficients has one row corresponding to each equation. The constants in that row are the coefficients of the variables in the equation. Coefficients are listed in the same order on each row. A missing term is represented by a coefficient of 0.
<h3>coefficient matrix, determinant</h3>
The first attachment shows the coefficient matrix and its determinant.
__
<h3>solution</h3>
The solution to the system of equations can be found by left-multiplying the constant vector by the inverse of the coefficient matrix.
This multiplication is shown in the second attachment. It tells us ...
{\text{Direction of parabola depends on the sign of quadratic coefficient of a }} \hfill \\
{\text{quadratic equation}}. \hfill \\
{\text{For given quadratic equation}}. \hfill \\
a{x^2} + bx + c = 0 \hfill \\
{\text{The parabola is in the upward direction if }}a{\text{ }} > {\text{ }}0{\text{ and in downward direction if }}a < 0 \hfill \\
{\text{Here, the equation of given parabola is }} \hfill \\
{x^2} - 6x + 8 = y \hfill \\
\Rightarrow y = \left( {{x^2} - 6x + 9} \right) - 9 + 8 \hfill \\
\Rightarrow y = {\left( {x - 3} \right)^2} - 1. \hfill \\
{\text{Thus, the parabola is in the upward direction}} \hfill \\