Answer:
1. False
2. True
3. True
Explanation:
1- False —> The relation between electric potential and electric field is given such that
![-\int\limits^a_b \vec{E}d\vec{l} = V_{ab}](https://tex.z-dn.net/?f=-%5Cint%5Climits%5Ea_b%20%5Cvec%7BE%7Dd%5Cvec%7Bl%7D%20%3D%20V_%7Bab%7D)
Therefore, for a uniform E field, electric potential is linearly proportional to the distance.
2- True —> The electric field lines always cross the equipotential lines perpendicularly.
3- True —> In order to be a potential difference, one source of electric field is enough. The electric potential will decrease radially according to the following formula:
![V = \frac{1}{4\pi\epsilon_0}\frac{q}{r^2}](https://tex.z-dn.net/?f=V%20%3D%20%5Cfrac%7B1%7D%7B4%5Cpi%5Cepsilon_0%7D%5Cfrac%7Bq%7D%7Br%5E2%7D)
There is no test charge in the formula, only the source charge. Even when there is no test charge, the potential difference between points in space can exist.
First, we need to fight the weight of the balls instead of their mass. We do this by multiplying their weight it kg by 9.8. This gives us .98 N. To find the potential energy of the rolling ball, we find its kinetic energy. The formula for this is KE=mass*velocity^2*1/2.
Plugging in our numbers, we have Kinetic energy = .1 * 1^2*1/2 which gives us .05 joules.
Now we find the potential energy of the ball on the shelf. For this we do:
Potential energy = .1*9.8*1, and our answer is .98 joules. Clearly, the ball on the shelf has more energy.
Each time you add a bulb it would probably get more dim. I think. Hope this helps XD
Answer: The speed of the student is 5.45km/hr.
Explanation: The important concept here is to convert 33 minutes to hours by diving by 60 since one hour is equal to 60 minutes to get 0.55hr
Then velocity is equal to distance over time.
v=d/t
v= 3km/0.55hr
v=5.45km/hr
The answer is D
I would have shown the explanation but it’s too much sorry