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evablogger [386]
3 years ago
8

a .1-kilogram ball rolls across the floor at a speed of 2 meters per second. Another .1 kilogram ball rests on a shelf 1 meter a

bove the floor. Which ball has more energy?
Physics
1 answer:
JulsSmile [24]3 years ago
6 0
First, we need to fight the weight of the balls instead of their mass.  We do this by multiplying their weight it kg by 9.8.  This gives us .98 N.  To find the potential energy of the rolling ball, we find its kinetic energy.  The formula for this is KE=mass*velocity^2*1/2.  

Plugging in our numbers, we have Kinetic energy = .1 * 1^2*1/2 which gives us .05 joules.

Now we find the potential energy of the ball on the shelf.  For this we do:

Potential energy = .1*9.8*1, and our answer is .98 joules.  Clearly, the ball on the shelf has more energy.
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Compare the maximum rate of heat transfer to the basal metabolic rate by converting a bmr of 88 kcal/hr into watts. what is the
elena-14-01-66 [18.8K]

Explanation :

It is given that,

BMR i.e basal metabolic rate is 88 kcal/hr. So, BMR in watts is converted by the following :

We know that, 1 kilocalorie = 4184 joules

So, 1\ kcal/h=\dfrac{1\times 4184\ J}{3600\ sec}

1\ kcal/h=1.16\ J/sec

J/sec is nothing but watts.

So, 1\ kcal/h=1.16\ watts

and 88\ kcal/h=88\times 1.16\ watts = 102.08\ watts

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8 0
3 years ago
If the area of an iron rod is 10 cm by 0.5 cm and length is 35 cm. Find the value of resistance, if 11x10^-8 ohm.m be the resist
malfutka [58]

Answer:

Resistance of the iron rod, R = 0.000077 ohms    

Explanation:

It is given that,

Area of iron rod, A=10\ cm\times 0.5\ cm=5\ cm^2 = 0.0005\ m^2

Length of the rod, L = 35 cm = 0.35 m

Resistivity of Iron, \rho=11\times 10^{-8}\ \Omega-m

We need to find the resistance of the iron rod. It is given by :

R=\rho\dfrac{L}{A}

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So, the resistance of the rod is 0.000077 ohms. Hence, this is the required solution.

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2 years ago
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