1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
iris [78.8K]
3 years ago
12

Answer True or Flase1-Electric potential due to a uniform E field doesn’t change with location.2-The equipotential surfaces asso

ciated with a uniform E field consist of a family of planes that are perpendicular to the E field.3-The electric potential difference between two locations can exist when there is only a source charge. Even when there is no TEST charge q, the potential difference can exist between two points in the space.
Physics
1 answer:
TEA [102]3 years ago
3 0

Answer:

1. False

2. True

3. True

Explanation:

1- False —> The relation between electric potential and electric field is given such that

-\int\limits^a_b \vec{E}d\vec{l} = V_{ab}

Therefore, for a uniform E field, electric potential is linearly proportional to the distance.

2- True —> The electric field lines always cross the equipotential lines perpendicularly.

3- True —> In order to be a potential difference, one source of electric field is enough. The electric potential will decrease radially according to the following formula:

V = \frac{1}{4\pi\epsilon_0}\frac{q}{r^2}

There is no test charge in the formula, only the source charge. Even when there is no test charge, the potential difference between points in space can exist.

You might be interested in
The stemplot below shows the heights (in inches) of students in a class.
masha68 [24]
B.b 70 would be the answer
4 0
4 years ago
Read 2 more answers
The relationship between energy (E), power (P), and time (t) is
NemiM [27]

Answer:

The avarage power of the body is 96.898 watts.

Explanation:

We must notice that given definition of power implies a constant consumption of energy, so that we should assume that energy consumption is constant. A Calorie is equal to 4186 joules. If we know that E = 2000\,Cal and t = 1\,day, the power of body, measured in watts, is:

P = \frac{(2000\,Cal)\cdot \left(4186\,\frac{J}{Cal} \right)}{(1\,day)\cdot \left(24\,\frac{h}{day} \right)\cdot \left(3600\,\frac{s}{h} \right)}

P = 96.898\,W

The avarage power of the body is 96.898 watts.

3 0
4 years ago
150kg object takes 1.5minutes to travel 2,500 meter straight path it begins the trip traveling 120m/s and decelerates to a veloc
Free_Kalibri [48]
<h2>Answer:</h2>

Acceleration= -1.11 m/sec²


<h2>Explanation:</h2>

Date Given to us is

Mass = 150 kg

Time = 1.5 minutes = 90 seconds

Distance = 2500 meters

Initial Velocity = 120 m/s

Final Velocity = 20 m/s

Acceleration = ?

<u>Solution:</u>

By using First Equation of motion

Vf = Vi + at

Putting the values

20 = 120 + a (90)

Subtracting 120 on both sides

20-120 = 120 + a(90) - 120

-100 = 90 a

Dividing both sides by 90

-100/90 = 90 a / 90

-1.11 = a

So the acceleration is -1.11 m/s²

3 0
4 years ago
The table below shows the right ascensions of two stars at a location.
zlopas [31]
Star 1 - 4 hours right ascension
 Star 2 - 3 hours right ascension
 Subtracting hours right ascension
 4 hours right ascension - 3 hours right ascension = 1 hours right ascension.
Thus,
 1) star 1 will rise 1 hour before star 2
5 0
3 years ago
The absolute pressure in water at a depth of 5m is read to be 145 kPa. Determine (a) the local atmospheric pressure, and (b) the
irga5000 [103]

Answer:

a) 95950 pascals

b) 137642.5 pascals

Explanation:

The absolute pressure (Pabs) on a fluid is:

P_{abs}=P_{gauge}+P_{atm} (1)

With Pgauge the pressure due depth on the fluid and Patm the atmospheric pressure. Pgauge is equal to:

P_{gauge}=\rho gh (2)

with ρ the fluid density, g the gravitational acceleration and h the depth on the fluid. Using (2) on (1) and solving for Patm:

P_{atm}=P_{abs}-P_{gauge}=P_{abs}-\rho_{water} gh

P_{atm}=(145000Pa)-(1000\frac{kg}{m^{3}})(9.81\frac{m}{s^{2}})(5m)

P_{atm}=95950Pa

b) Here we're going to use again (1) but now we have another value of density because it's other liquid, to know that value we should use the fact that specific gravity (S.G) for liquids is the ratio between fluid density and water density:

S.G=\frac{\rho_{fluid}}{\rho_{water}}

\rho_{liquid}=S.G*\rho_{water}

\rho_{liquid}=(0.85)*(1000\frac{kg}{m^{3}})=850\frac{kg}{m^{3}}

so:

P_{abs}=\rho_{liquid} gh+P_{atm}=(850\frac{kg}{m^{3}})(9.81\frac{m}{s})(5m)+95950Pa

P_{abs}=137642.5 Pa

3 0
3 years ago
Other questions:
  • please help!!!!!what is the main function of a telescope? A.it brings scientists closer to distant obejects B. it magnifies ligh
    5·2 answers
  • Considering thermal equilibrium in your answer, explain why some materials feel different temperatures.
    9·1 answer
  • Which of the angles shown in this picture is the angle of incidence?<br> A<br> B
    8·2 answers
  • Which subatomic particle can be absent from an atom?
    15·1 answer
  • If a child needs interventional service, he or she might have _____.
    11·1 answer
  • Energy is the ability to___or___ matter​
    13·1 answer
  • What best describes why kepler’s observation of planetary motion is a law instead of a theory
    11·1 answer
  • What is the power of ideal sunglass​
    9·2 answers
  • Observing and experimenting are two ways that ecologists can answer scientific questions. What are some differences between thes
    10·1 answer
  • The products obtained at cathode during electrolysis depends on the nature of electrodes and electrolyte used.
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!