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4 years ago

According to this graph, which statement describes how the amount of iron changes over time in the reaction

1 answer:

5 0

The graph shows the production of Fe, from the graph that it increases rapidly and then slowly increases.<span>The answer is a! (:
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Which of the following elements is in Group 2?

Rzqust [24]

Answer:

calcium

Explanation:

if you have a periodic table that would be very helpful to you

6 0

3 years ago

What is the application of a spherometer in the medical field?

Anton [14]

Answer:

To correct the defects of vision by measuring the radius of curvature and thus the power of the lenses.

Explanation:

A spherometer is an instrument used to measure the curvature of objects such as lenses and curved mirrors.

Generally it consists of a fine screw which is moving in a nut carried on the center of a 3 small legged table or frame. The feet forms the vertices of an equilateral triangle. The lower end of the screw and those of the table legs are finely tapered and terminate in hemispheres.

If the screw has two turns of the thread to the milli meter the head is generally divided into 50 equal parts, so that differences of 0.01 millimeter may be measured without using a vernier scale.

The spherometer is used to measure the radius of curvature of the lenses so that the opthalmologist find the focal length of the lens and then give the power to the lens to correct the defects of vision.

8 0

3 years ago

Driving along a crowded freeway, you notice that it takes a time tt to go from one mile marker to the next. When you increase yo

ddd [48]

Answer:

38.6 mi/h

Explanation:

7.4 mi/h = 7.4mi/h * (1/60)hour/min * (1/60) min/s = 0.00206 mi/s

Let v (mi/s) be your original speed, then the time t it takes to go 1 mi/s is

t = 1/v

Since you increase v by 0.00206 mi/s, your time decreases by 15 s, this means

t - 15 = 1/(v+0.00206)

We can substitute t = 1/v to solve for v

$\frac{1}{v} - 15 = \frac{1}{v + 0.00206}$

We can multiply both sides of the equation with v(v+0.00206)

v+0.00206 - 15v(v+0.00206) = v

$-15v^2 - 0.0308v + 0.00206 = 0$

$v= \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$

$v= \frac{0.03083\pm \sqrt{(-0.03083)^2 - 4*(-15)*(0.00205)}}{2*(-15)}$

$v= \frac{0.03083\pm0.35}{-30}$

v = -0.01278 or v = 0.01 0724 mi/s

Since v can only be positive we will pick v = 0.010724 mi/s or 0.010724*3600 = 38.6 mi/h

6 0

4 years ago

Which of the following describes how cooling

wel

I think it is C because it makes more sense

4 0

4 years ago

Consider a series RLC circuit where R = 855 Ω and C = 6.25 μF. However, the inductance L of the inductor is unknown. To find its

sashaice [31]

Answer:

L= 0.059 mH

Explanation:

Given that

R = 855 Ω and C = 6.25 μF

V= 84 V

Frequency

ω = 51900 1/s

We know that

$\omega=\sqrt{\dfrac{1}{LC}}$

L=Inductance

C=Capacitance

ω =angular Frequency

ω² L C =1

(51900)² x L x 6.25 x 10⁻⁶ = 1

L= 5.99 x 10⁻⁵ H

L= 0.059 mH

6 0

4 years ago