1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Marianna [84]
3 years ago
13

Jillian is mailing an 8-pound package. She doesn’t know a single conversion factor that will convert pounds to grams. Which conv

ersion factors can you use to find the weight in grams? Check all that apply.
Mathematics
2 answers:
cricket20 [7]3 years ago
7 0
For this case we have the following conversion of units:
 1 lb = 453.59 g
 We apply the conversion of units to the weight of the package.
 We have then:
 (8) * (453.59) = 3628.72 g
 Answer:
 
the weight in grams is:
 
3628.72 g.
 
you can use the following conversion factor:
 
1 lb = 453.59 g
Colt1911 [192]3 years ago
3 0

Answer:

first and last option

Step-by-step explanation:

You might be interested in
What is the greatest common factor of 49, 62 and 80?
steposvetlana [31]

Answer:

literally 1

Step-by-step explanation:

scooby ate my scooby snax

6 0
2 years ago
Read 2 more answers
What is m2?<br> What is m&lt;1?
yuradex [85]

Answer:

∠ 2 = 75° , ∠ 1 = 105°

Step-by-step explanation:

∠ 2 and 75° are alternate angles and are congruent , then

∠ 2 = 75°

∠ 1 and ∠ 2 are a linear pair and sum to 180° , that is

∠ 1 + ∠ 2 = 180°

∠ 1 + 75° = 180° ( subtract 75° from both sides )

∠ 1 = 105°

3 0
1 year ago
What is the GCF of 42 and 90
ozzi
The answer is 6. hope this helps
8 0
2 years ago
Read 2 more answers
Percy paid $24. 10 for a basketball. The price of the basketball was $22. 99. What was the sales tax rate?.
Alika [10]

Answer:

$3.11

Step-by-step explanation:

you have to subtract 24.10 from 22.99

6 0
1 year ago
Read 2 more answers
Quantitative noninvasive techniques are needed for routinely assessing symptoms of peripheral neuropathies, such as carpal tunne
Pavlova-9 [17]

Answer:

t=\frac{2.35-1.83}{\sqrt{\frac{0.88^2}{10}+\frac{0.54^2}{7}}}}=1.507  

p_v =P(t_{(15)}>1.507)=0.076

If we compare the p value and the significance level given \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and the group CTS, NOT have a significant higher mean compared to the Normal group at 1% of significance.

Step-by-step explanation:

1) Data given and notation

\bar X_{CTS}=2.35 represent the mean for the sample CTS

\bar X_{N}=1.83 represent the mean for the sample Normal

s_{CTS}=0.88 represent the sample standard deviation for the sample of CTS

s_{N}=0.54 represent the sample standard deviation for the sample of Normal

n_{CTS}=10 sample size selected for the CTS

n_{N}=7 sample size selected for the Normal

\alpha=0.01 represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

p_v represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean for the group CTS is higher than the mean for the Normal, the system of hypothesis would be:

Null hypothesis:\mu_{CTS} \leq \mu_{N}

Alternative hypothesis:\mu_{CTS} > \mu_{N}

If we analyze the size for the samples both are less than 30 so for this case is better apply a t test to compare means, and the statistic is given by:

t=\frac{\bar X_{CTS}-\bar X_{N}}{\sqrt{\frac{s^2_{CTS}}{n_{CTS}}+\frac{s^2_{N}}{n_{N}}}} (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other".

Calculate the statistic

We can replace in formula (1) the info given like this:

t=\frac{2.35-1.83}{\sqrt{\frac{0.88^2}{10}+\frac{0.54^2}{7}}}}=1.507  

P-value

The first step is calculate the degrees of freedom, on this case:

df=n_{CTS}+n_{N}-2=10+7-2=15

Since is a one side right tailed test the p value would be:

p_v =P(t_{(15)}>1.507)=0.076

We can use the following excel code to calculate the p value in Excel:"=1-T.DIST(1.507,15,TRUE)"

Conclusion

If we compare the p value and the significance level given \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and the group CTS, NOT have a significant higher mean compared to the Normal group at 1% of significance.

6 0
3 years ago
Other questions:
  • The sum of 3 consecutive even integers is 18<br>​
    7·1 answer
  • A theater company has raised $930.75 by selling 25 floor seat tickets. Each ticket costs the same.
    9·1 answer
  • Can someone please help me?
    11·1 answer
  • What is 25% of 15<br> Please help thank you!
    15·2 answers
  • Rearrange the following equation to solve for x. y=1/2x+10
    13·1 answer
  • Jane says that she can use addition to show that the graphs of 2x - 3y = 1 and 2x + 3y = 2 are intersecting lines. In two or mor
    9·1 answer
  • What is the value of m?<br> O 10<br> O 30<br> O 70<br> O 150
    10·1 answer
  • Make a tree diagram which shows the sample space of rolling a cube with faces numbered 1-6 and flipping a fair coin. Using this
    14·1 answer
  • The mean of 4 numbers is 19. What would the new mean be if the number 30 is added to the data set?
    14·1 answer
  • HELP ME ASAP!!!
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!