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Alex777 [14]
3 years ago
9

DO,-2(x, y)(3, 5). The point (x, y) is

Mathematics
2 answers:
skelet666 [1.2K]3 years ago
8 0

Answer:

The point (x,y) is (\dfrac{-3}{2},\dfrac{-5}{2}).

Step-by-step explanation:

We are given that,

D_{0,-2}(x,y)=(3,5)

That is,

<h3><em>The image of the point (x,y) after dilation with center as the origin and scale factor -2 is (3,5).</em></h3>

So, we get,

\dfrac{3}{x}=-2\\\\x=\dfrac{-3}{2}

\dfrac{5}{y}=-2\\\\x=\dfrac{-5}{2}

Thus, the point (x,y) is (\dfrac{-3}{2},\dfrac{-5}{2}).

irina1246 [14]3 years ago
7 0
I believe it's (-6, -10) I'm pretty sure..
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What are the roots to<br> the equation<br> 2x² + 6x-1=0?
lys-0071 [83]

Answer:

The roots of  equations are as m =  \frac{-3}{2} + \frac{\sqrt{11} }{2}  And n =  \frac{-3}{2} - \frac{\sqrt{11} }{2}    

Step-by-step explanation:

The given quadratic equation is 2 x² + 6 x - 1 = 0

This equation is in form of a x² + b x + c = 0

Let the roots of the equation are ( m , n )

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And products of roots = \frac{c}{a}

So, m + n = \frac{ - 6}{2} = - 3

And m × n =  \frac{ - 1}{2}

Or, (m - n)² = (m + n)² - 4mn

Or, (m - n)² = (-3)² - 4 (\frac{ - 1}{2})

Or, (m - n)² = 9 + 2 = 11

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