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Alex777 [14]
4 years ago
9

DO,-2(x, y)(3, 5). The point (x, y) is

Mathematics
2 answers:
skelet666 [1.2K]4 years ago
8 0

Answer:

The point (x,y) is (\dfrac{-3}{2},\dfrac{-5}{2}).

Step-by-step explanation:

We are given that,

D_{0,-2}(x,y)=(3,5)

That is,

<h3><em>The image of the point (x,y) after dilation with center as the origin and scale factor -2 is (3,5).</em></h3>

So, we get,

\dfrac{3}{x}=-2\\\\x=\dfrac{-3}{2}

\dfrac{5}{y}=-2\\\\x=\dfrac{-5}{2}

Thus, the point (x,y) is (\dfrac{-3}{2},\dfrac{-5}{2}).

irina1246 [14]4 years ago
7 0
I believe it's (-6, -10) I'm pretty sure..
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A regular pentagon has an apothem measuring 20 cm and a perimeter of 145. 3 cm. A rectangular pentagon has an apothem measuring
Effectus [21]

The area of the pentagon is 1,453 squared centimeters.

Given information-

The length of the apothem of a regular pentagon is 20 cm.

The measure of the perimeter of a regular pentagon is 145.3 cm.

The length of the apothem of a rectangular pentagon is 20 cm.

The measure of the perimeter of a rectangular pentagon is 145.3 cm.

<h3>Pentagon-</h3>

Pentagon is the closed shaped polygon which has 5 sides. When these 5 sides are equal in length then the pentagon is called teh regular pentagon. When four of the sides of pentagon make a rectangle then the pentagon is called the rectangular pentagon.

<h3>Area of regular pentagon-</h3>

Area of regular pentagon is half of the product of its apothem and perimeter. It can be given as,

A=\dfrac{1}{2} \times 20\times 145.3\\A=1453

Thus the area of the pentagon is 1,453 squared centimeters.

Learn more about the regular pentagon here;

brainly.com/question/858867

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For the reaction,

CO(g) + H_2 O(g) = CO_2(g) + H_2(g)

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<u>0.1M</u> , <u>0.1M</u> , <u>0</u> , <u>0</u>

Let 'x' mole per litre of each of theproduct be formed.

At equilibrium:

<u>(0.1 – x)M</u> , <u>(0.1 – x)M</u> , <u>xM</u> , <u>xM</u>

where x is the amount of Carbon dioxide and Hydrogen, at equilibrium.

Hence, equilibrium constant can be written as,

K_c = \frac{x²}{(0.1 – x)²} = 4.24

→ x² = 4.24 (0.01 + x² – 0.2x)

→ x² = 0.0424 + 4.24 x² - 0.848x

→ 3.24x² - 0.848x + 0.0424 = 0

<em>a = 3.24, b = -0.848, c = 0.0424</em>

(for quadratic equation ax² + bx+c=0)

x =  \frac{( - b \: ± \: \sqrt{ {b}^{2} - 4ac) } }{2a}

=  > x =  \frac{ - ( - 0.848 \: ± \:  \sqrt{( - 0.848)^{2} - 4(3.24)(0.0424) } }{2 \times 3.24}

=  > x =  \frac{ - 0.848±0.4118}{6.48}

x_1 =  \frac{0.848 - 0.4118}{6.48} = 0.067

x_2 =  \frac{0.848 + 0.4118}{6.48} = 0.194

Here, the value 0.194 should be neglected because it will give concentration of the reactant which is more than initial concentration.

∴ The equilibrium concentrations are :-

[CO_2] [H_2] = x = 0.067M

[CO] [H_2 O] = 0.1 - 0.067 = 0.033M

7 0
3 years ago
A man is standing at a radar base and observes an unidentified plane at an altitude 6000m flying towards the radar base at an an
liubo4ka [24]

Answer:

The speed in of the plane is 115.47 m/sec

Step-by-step explanation:

Given:

Height at which the plane is flying = 6000 m

Angle of elevation at the radar base = 30 Degrees

Angle of elevation at the radar base after one minute  = 60 Degrees

To Find:

The Speed of the plane in meter per second = ?

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Let us use the tangent of the angle to find the distance (d) to a point directly below plane:

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tan(30) = \frac{6000}{d1}

d1   = \frac{6000}{tan(30)}

d1 = \frac{6000}{0.577}

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tan(60) = \frac{6000}{d2}

d2  = \frac{6000}{tan(60)}

d2  = \frac{6000}{1.732}\\

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<u>distance travelled by aircraft in 1 min is  </u>

=>d1 - d2

=>0392.3 - 3464.1

= 6928.2 m/min

<u>Now converting to m/sec</u>

=>\frac{6928.2}{60}

=>115.47 m/sec

4 0
3 years ago
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