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Licemer1 [7]
3 years ago
7

ASAPPP!!!!!

Mathematics
1 answer:
Sergio039 [100]3 years ago
5 0

Answer:

185

Step-by-step explanation:

45 +70(2) = 185

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The power is the probability that the assembly process is not stopped when it should be because a high number of defective items
choli [55]

Answer:

B. The power is the probability that the assembly process continues because the proportion of items that must be rejected has not increased.

Step-by-step explanation:

The probability is the percentage which determines the occurrence of an event. The probability measure is of power determines that the assembly process will continue because the proportion of the items that must be rejected is not increased.

4 0
3 years ago
Simplify the expression: show all ur steps/ wrk PLEASE,1+2x3-18/3+(5(2+2)]
Maurinko [17]
Ok let's do this*pops knuckles*



let's add the first side

1 + 2 \times 3 - 18
order of operations demands that we do multiplication first(P.E.M.D.A.S)

so
2 \times 3 = 6
now we can add the 1 from
1 + (6) - 18
into our six


6 + 1 = 7
now we substract

(7) - 18 =  - 11
now we have
- 11  \div 3 + (5(2 + 2))
now we focus on the
other side
3 + (5(2 + 2))
since 5 is in paranthesis we use something called the distributive property. it mean we will multiply the 5 by both of the 2.
(5(2 + 2)) = (((5 \times 2) + (5 \times 2) = 20
now we have
3  + 20 = 23

(the three is from the original equation)

now we plug in our final numbers

- 11 \div 23
or
\frac{ - 11}{23}
I hope this helps
4 0
3 years ago
Read 2 more answers
What is the common denominator of 14 and 8
Akimi4 [234]
It would be 56. The LCM of 14 and 8 is 56.
6 0
3 years ago
Read 2 more answers
Please Help <br> Question Is In the picture!!
Tema [17]

Answer: big boi like a someboody 2x -853

Step-by-step explanation:

4 0
3 years ago
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For number 6, evaluate the definite integral.
maks197457 [2]
\bf \displaystyle \int\limits_{0}^{28}\ \cfrac{1}{\sqrt[3]{(8+2x)^2}}\cdot dx\impliedby \textit{now, let's do some substitution}\\\\&#10;-------------------------------\\\\&#10;u=8+2x\implies \cfrac{du}{dx}=2\implies \cfrac{du}{2}=dx\\\\&#10;-------------------------------\\\\

\bf \displaystyle \int\limits_{0}^{28}\ \cfrac{1}{\sqrt[3]{u^2}}\cdot \cfrac{du}{2}\implies \cfrac{1}{2}\int\limits_{0}^{28}\ u^{-\frac{2}{3}}\cdot du\impliedby &#10;\begin{array}{llll}&#10;\textit{now let's change the bounds}\\&#10;\textit{by using } u(x)&#10;\end{array}\\\\&#10;-------------------------------\\\\&#10;u(0)=8+2(0)\implies u(0)=8&#10;\\\\\\&#10;u(28)=8+2(28)\implies u(28)=64

\bf \\\\&#10;-------------------------------\\\\&#10;\displaystyle  \cfrac{1}{2}\int\limits_{8}^{64}\ u^{-\frac{2}{3}}\cdot du\implies \cfrac{1}{2}\cdot \cfrac{u^{\frac{1}{3}}}{\frac{1}{3}}\implies \left. \cfrac{3\sqrt[3]{u}}{2} \right]_8^{64}&#10;\\\\\\&#10;\left[ \cfrac{3\sqrt[3]{(2^2)^3}}{2} \right]-\left[ \cfrac{3\sqrt[3]{2^3}}{2}  \right]\implies \cfrac{12}{2}-\cfrac{6}{2}\implies 6-3\implies 3
3 0
3 years ago
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