Let the number of large bookcases be x and number of small bookcases be y, then
Maximise P = 80x + 50y;
subkect to:
6x + 2y ≤ 24
x, y ≥ 2
The corner points are (2, 2), (2, 6), (3.333, 2)
For (2, 2): P = 80(2) + 50(2) = 160 + 100 = 260
For (2, 6): P = 80(2) + 50(6) = 160 + 300 = 460
For (3.333, 2): P = 80(3.333) + 50(2) = 266.67 + 100 = 366.67
Therefore, for maximum profit, he should produce 2 large bookcases and 6 small bookcases.
Here is a method that makes it seem easier.
<span>Write down any number between 51 and 59. </span>
<span>For example you might choose 57 = 3*19 </span>
<span>Divide both numbers by 10 and write the answer as </span>
<span>0.3 * 1.9 = 0.57</span>
<span>5/ 8 x 4/ 5
=20/40
=1/2
answer is </span>A. 1/2
1) is false, it is always a rhombus.
2) is true, a rectangle with all sides equal would be a square.
3) is false, a kite's side lengths must be 2 pairs of unequal lengths.
4) is true, a square is a rhombus that has 90-degree angles.
5) is true, a kite must have 2 pairs of unequal lengths, but a trapezoid cannot have exactly 2 sides of equal lengths.
Answer:
The case is ten pounds.
Step-by-step explanation:
There are 16 ounces in a pound. Using this information, you can multiply the ounces by the 64 boxes. Then divide the product by 16. You should be left with 10 pounds.
