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cricket20 [7]
3 years ago
6

What element in the fourth period is an exception to the Aufbau principle?

Chemistry
1 answer:
bogdanovich [222]3 years ago
6 0
The answer would be Cr
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Zinc metal can be obtained from Zinc Oxide by reaction at high temperature with CO. The CO is obtained from burning C in limited
bonufazy [111]

Answer:

(a): 2ZnO(s) -----------> 2Zn(s) + O2(g)

2C(s) + O2(g) ---------> 2CO(g)

(b): ZnO(s) + C(s) ---------> Zn(s) + CO(g)

3 0
3 years ago
When you combine 50.0 mL of 0.100 M AgNO3 with 50.0 mL of 0.100 M HCl in a coffee-cup calorimeter, the temperature changes from
RideAnS [48]

Answer : The enthalpy of reaction (\Delta H_{rxn}) is, 67.716 KJ/mole

Explanation :

First we have to calculate the moles of AgNO_3 and HCl.

\text{Moles of }AgNO_3=\text{Molarity of }AgNO_3\times \text{Volume}=(0.100mole/L)\times (0.05L)=0.005mole

\text{Moles of }HCl=\text{Molarity of }HCl\times \text{Volume}=(0.100mole/L)\times (0.05L)=0.005mole

Now we have to calculate the moles of AgCl formed.

The balanced chemical reaction will be,

AgNO_3(aq)+HCl(aq)\rightarrow AgCl(s)+HNO_3(aq)

As, 1 mole of AgNO_3 react with 1 mole of HCl to give 1 mole of AgCl

So, 0.005 mole of AgNO_3 react with 0.005 mole of HCl to give 1 mole of AgCl

The moles of AgCl formed  = 0.005 mole

Total volume of the solution = 50.0 ml + 50.0 ml = 100.0 ml

Now we have to calculate the mass of solution.

Mass of the solution = Density of the solution × Volume of the solution

Mass of the solution = 1.00 g/ml × 100.0 ml = 100 g

Now we have to calculate the heat.

q=m\times C\Delta T=m\times C \times (T_2-T_1)

where,

q = heat

C = specific heat capacity = 4.18J/g^oC

m = mass = 100 g

T_2 = final temperature = 24.21^oC

T_1 = initial temperature = 23.40^oC

Now put all the given values in the above expression, we get:

q=100g\times (4.18J/g^oC)\times (24.21-23.40)^oC

q=338.58J

Now  we have to calculate the enthalpy of the reaction.

\Delta H_{rxn}=\frac{q}{n}

where,

\Delta H_{rxn} = enthalpy of reaction = ?

q = heat of reaction = 338.58 J

n = moles of reaction = 0.005 mole

Now put all the given values in above expression, we get:

\Delta H_{rxn}=\frac{338.58J}{0.005mole}=6771.6J/mole=67.716KJ/mole

Conversion used : (1 KJ = 1000 J)

Therefore, the enthalpy of reaction (\Delta H_{rxn}) is, 67.716 KJ/mole

4 0
3 years ago
Does the energy go from the surrounding to the chemicals or from the chemicals to the surround in an exothermic reaction?
Karo-lina-s [1.5K]
In general terms, exothermic reactions release energy, so the energy goes from the system to the surroundings.
4 0
3 years ago
How do the bonds differ in<br> each type?
VashaNatasha [74]

Answer:

Bonds basically differs with each other due to sharing of electrons .

Explanation:

There are majorly three kinds of bonds

1. Ionic bonds which forms due to an element donate an electron to another element completely .

2. covalent bonds which forms with the mutual sharing of electrons b/w two atoms .

3. metallic bonds which forms b/w metals & they share electrons due to electron negativity difference b/w two atoms or elements

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3 years ago
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About how many millions of tons of paper and paperboard were consumed worldwide in 1970? 1980? 1990? 2000?
ad-work [718]

2000 IS RIGHT BECAUSE IT IS

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4 years ago
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