Answer:
74,67 gr/mol
Explanation:
At STP 1 mole of an ideal gas has volume of 22,4 L. Since we know the volume of the gas we can find the number of moles of the gas. (300 mL=0,3 L)
n=0,3L/22,4 L=0,01339 mol
Since we know weight of the gas as 1 g, we can find the molecular weight as;
MW=1 g/0,01339 mol =74,67 gr/mol
The right answer for the question that is being asked and shown above is that: "C) carbon monoxide and carbon dioxide" hydrocarbons burn completely in an excess of oxygen, the products are <span>C) carbon monoxide and carbon dioxide</span>
By the word alphabet, derived from the Greek names for the first two letters - alpha and beta<span> - of the Greek alphabet, is meant a series of conventional symbols each indicating a single sound or combination of sounds</span><span>
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Moles of NH3 = mass of NH3/molecular mass of NH3 = 1.7/17= O.1 MOLES.
<span>The answer to this would be radioactive decay. This is also known as "nuclear decay" or "radioactivity".</span>
