If two fatty acids, glycerol, and a phosphate group undergo a dehydration reaction, what molecule forms
1 answer:
<h3>Answer:</h3>
A Phospholipid is formed.
<h3>Explanation:</h3>The reaction of fatty acids, glycerol and phosphoric acid is given below. In this reaction the carboxylic groups of fatty acids and the hydrogyl groups of glycerol undergo an Esterification Reaction with the elimination of two water molecules and formation of Ester functional group. Also, the third hydroxyl group of glycerol undergo dehydration reaction with phosphoric acid. The resulting molecule is known as phospholipid.
Biologically, Phospholipids are found in the cell membranes. The long hydrocarbon chains of fatty acids acts as hydrophobic (water fearing) tails and the phosphate group acts as hydrophilic (water loving) head. They form a barrier protecting the internal environment of cell from external surrounding.
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Answer:
a. 123.9°C
b.
c.
Explanation:
Hello, I'm attaching a picture with the numerical development of this exercise.
a. Since the steam is overheated vapour, the specific volume is gotten from the corresponding table. Then, as it became a saturated vapour, we look for the interval in which the same volume of state 1 is, then we interpolate and get the temperature.
b. Now, at 80°C, since it is about a rigid tank (constant volume for every thermodynamic process), the specific volume of the mixture is 0.79645 m^3/kg as well, so the specific volume for the liquid and the vapour are taken into account to get the quality of 0.234.
c. Now,since this is an isocoric process, the heat transfer per kg of steam is computed as the difference in the internal energy, considering the initial condition (showed in a. part) and the final one computed here.
** The thermodynamic data were obtained from Cengel's thermodynamics book 7th edition.
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