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Karo-lina-s [1.5K]
3 years ago
8

Given that , the _____ justifies the conclusion that ∆ABD ≅ ∆AEC.

Mathematics
2 answers:
Mariulka [41]3 years ago
6 0
The answer to your question is ASA postulate
trasher [3.6K]3 years ago
3 0
AAS Postulate

It is given that CE = BD so we know "S" (representing side) has to be in the three letter postulate.
It is also given that angle DBA and angle CEA are right angles, so therefore they are congruent. Now we know that an "A" must also be in the postulate.

Lastly, we know that the triangles have a second angle, EAB, in common because they share it overlappingly. So there must be another "A" in the postulate. 

Now we need to look at the order in which it is presented. The order follows Angle, Angle, Side so the postulate must be the AAS postulate. Hope this helps!

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I am sooooo dumb i swear,
Citrus2011 [14]

Hei dere!

So this is how I learned it:

18         x

----  =  -------

60       100

Cross cancel it:

60x=1800

x=30%

Hope I helped!

~Potato.

Copyright Potato 2019.

5 0
3 years ago
Can someone please help me, this is the last question on my test and I dont understand. please and thanks.
Elina [12.6K]

Step-by-step explanation:

A: ←⭕

B: •→

C: ←•

D: ⭕→

.........

4 0
2 years ago
Read 2 more answers
What is 35% of 80 ?<br> A<br> 15<br> B.<br> 24<br> С<br> 28<br> D<br> 52
Evgen [1.6K]
The answer is C 28 I hope this helped :)
8 0
2 years ago
What are the coordinates of the hole in the graph of the function?
MakcuM [25]

Answer:

The hole is at (5,7)

Step-by-step explanation:

x^2 − 3x − 10

-------------------

x−5

Factor the numerator

(x-5)(x+2)

-------------------

x−5

There is a hole at x=5 since it will cancel in the numerator and the denominator

f(x) = x+2  and letting x = 5

f(5) = 5+2

The hole is at (5,7)

4 0
3 years ago
Help me pls.
salantis [7]

Answer:

1. 424

2.471

3.512

Step-by-step explanation:

1. 10×12+8×10+8×13+8×15

=120+80+104+120

=424

2. 5×24+9×24+9×15+9×15

=120+216+135

=471

3. 24×16+2×24+2×20+2×20

=384+48+40+40

=512

3 0
3 years ago
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