Ask question

Ask question

All categories

3 years ago

5

A bug is sitting on the edge of a rotating disk. At what angular velocity will the bug slide off the disk if its radius is 0.241

m, the coefficient of static friction between the bug and disk is 0.321, and the coefficient of kinetic friction is 0.102

1 answer:

Ivahew [28]3 years ago

3 0

Answer:

ω = 3.61 rad/sec

Explanation:

Firstly, we should know that the bug will not slip if friction can provide sufficient opposing force.

μmg = mv^2/r = mω^2r

Thus;

μg = ω^2r

ω^2 = μg/r

ω = √(μg/r)

ω = √(0.321 * 9.8)/0.241

ω = √(13.05)

= 3.61 rad/sec

You might be interested in

a coil of 40 henry inductance is connected in series with aresistance of 8ohm and the combination is joined to the terminals of

Andreyy89

Answer: 5 seconds

Explanation:

Given the following :

Inductance (L) = 40 henry

Resistance = 8 ohms

The circuit given above is a Resistor - Inductor (RL) circuit network. The time constant of an RL circuit is the ratio of the circuit Inductance (L) and Resistance (R). Time constant is measured in seconds.

THAT IS;

Time constant = L / R

THEREFORE ;

Time constant = 40 / 8

Time constant = 5 seconds

7 0

3 years ago

Your low-flow showerhead is delivering water at 1.2×10−4m3/s, about 2.0 gallons per minute.

Oksanka [162]

To solve this problem it is necessary to apply the fluid mechanics equations related to continuity, for which the proportion of the input flow is equal to the output flow, in other words:

$Q_1 = Q_2$

We know that the flow rate is equivalent to the velocity of the fluid in its area, that is,

$Q = VA$

Where

V = Velocity

A = Cross-sectional Area

Our values are given as

$Q_2 = 1.2*10^{-4}m^3/s$

$d = 0.021m$

$r = \frac{0.021}{2} = 0.0105m$

Since there is continuity we have now that,

$V_1A_1 = Q_2$

$V_1A_1 = 1.2*10^{-4}$

$V_1 = \frac{1.2*10^{-4}}{A_2}$

$V_1 = \frac{1.2*10^{-4}}{\pi r^2}$

$V_1 = \frac{1.2*10^{-4}}{\pi (0.0105)^2}$

$V_1 =0.347m/s$

Therefore the speed of the water's house supply line is 0.347m/s

7 0

3 years ago

If the net force acting on a stationary object is zero then the object will

Drupady [299]

If the net force is zero, then there is no acceleration, which means no change in velocity. The velocity starts at zero, so it must remain at zero. Therefore, the object will not move.

7 0

3 years ago

Through what potential difference must electrons be accelerated so that they will exhibit wave nature in passing through a pinho

Mila [183]

Answer:

0.15 mV

Explanation:

In order to exhibit wave nature, the de Broglie wavelength of the electron must be of the same size of the diameter of the pinhole, therefore:

$\lambda=0.10 \mu m = 1.0\cdot 10^{-7} m$

The de Broglie wavelength of an electron is

$\lambda = \frac{h}{mv}$

where

$h=6.63\cdot 10^{-34} Js$ is the Planck constant

$m=9.11\cdot 10^{-31} kg$ is the mass of the electron

v is the electron's speed

Therefore, the electron's speed must be

$v=\frac{h}{m\lambda}=\frac{6.63\cdot 10^{-34}}{(9.11\cdot 10^{-31})(1.0\cdot 10^{-7})}=7278 m/s$

When accelerated through a potential difference $\Delta V$ , the kinetic energy gained by the electron is equal to the change in electric potential energy, therefore

$e\Delta V = \frac{1}{2}mv^2$

where

$e=1.6\cdot 10^{-19}$ is the magnitude of the charge of the electron

So, we can find the potential difference needed:

$\Delta V=\frac{mv^2}{2e}=\frac{(9.11\cdot 10^{-31})(7278)^2}{2(1.6\cdot 10^{-19})}=1.5\cdot 10^{-4}V = 0.15 mV$

5 0

3 years ago

A surfactant with a Hydrophile-

zlopas [31]

Answer:

Explanation:

True

8 0

3 years ago