A bug is sitting on the edge of a rotating disk. At what angular velocity will the bug slide off the disk if its radius is 0.241

Question

3 years ago

5

m, the coefficient of static friction between the bug and disk is 0.321, and the coefficient of kinetic friction is 0.102

1 answer:

Ivahew [28] · Answer 1 · 2022-03-15T02:59:39+03:00

3 0

Answer:

ω = 3.61 rad/sec

Explanation:

Firstly, we should know that the bug will not slip if friction can provide sufficient opposing force.

μmg = mv^2/r = mω^2r

Thus;

μg = ω^2r

ω^2 = μg/r

ω = √(μg/r)

ω = √(0.321 * 9.8)/0.241

ω = √(13.05)

= 3.61 rad/sec