Question

the ratio of kinetic energy to the potential energy of a certain object of mass m at a height of 40 m above ground level is 2:1. What is the speed of the object at the point? Use g=10 m/s^2 A.)20 m/s B.)40 m/s C.)30 m/s D.) 10 m/s

Answer 1

I believe it is A)    2(1/2mv^2)=mgh   <===cross out masses
                           2(1/2V^2)=gh
                           
Solve for V