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evablogger [386]
3 years ago
13

A bicycle wheel has spokes for support. Each spoke extends from the center of the wheel to the rim. Which method can be used to

find the circumference of the bicycle wheel?
Physics
2 answers:
faltersainse [42]3 years ago
5 0
Formula:Pi x d .  pi times 2 times the length of the spoke.
hoa [83]3 years ago
3 0
Since the formula for the circumference of a circle is pi x d or pi x 2r. The radius is a straight line from the center of the circle to the outer part of it, which is exactly what the spokes are to the wheel. So we take the length of the spoke, which is the radius, and use it in our equation. pi times 2 times the length of the spoke will give us our answer.
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QUESTION 3
Alisiya [41]

The force of frictions is opposed to relative motion.

The acceleration of the crate is approximately <u>2.937 m/s²</u>.

Reason:

The given parameters are;

The mass of the wood, m = 100 kg

The force which can move the wood, F = 588 N

Wood on wood static friction, \mu_s = 0.5

Wood on wood kinetic friction, \mu_k = 0.3

Solution;

The force of friction, F_f, acting when the crate is moving is given as

follows;

F_f = m × g × \mu_k

Where;

g = The acceleration due to gravity ≈ 9.81 m/s²

Therefore, we have;

F_f = 100 × 9.81 × 0.3 = 294.3

The force of friction, F_f = 294.3 N

The force with which the crate moves, F = 588 - 294.3 = 293.7

The force with which the crate moves, F = 293.7 N

Force = Mass, m × Acceleration, a

a = \dfrac{F}{m}

Therefore;

a = \dfrac{293.7 \ N}{100 \ kg} = 2.937

The acceleration of the crate, a ≈ <u>2.937 m/s²</u>.

Learn more about friction here:

brainly.com/question/94428

8 0
2 years ago
In a particular run of the “Archimedes principle” experiment a particular unknown substance is found to have a “dry mass” of 4.5
iris [78.8K]

Answer:

D = 18000 kg/m3

V = 2.5*10{-7}m3

Explanation:

From the Archimedes principle,

Weight of fluid displaced = W_{air} - W_{water}

W_{air} = 4.5 gm

W_{water} = 4.25 gm

W = [4.5 - 4.25]*9.81*10^{-3}

W = 2.4525*10{-3} N

\frac{density\ of\ object}{density\ of\ fluid} = \frac{weight\ in\ air}{weight\ of\ displaced\ fluid}

Density\ of\ object = \frac{D_{water}*Weight\ in\ air}{weight\ of\ displaced\ water}

D = \frac{1000*4.5*10^{-3}*9.8}{2.4525*10^{-3}}N

D = 18000 kg/m3

b) object Volume can be obtained  as ,

V = \frac{m}{D} = \frac{4.5*10^{-3}}{18000}

V = 2.5*10{-7}m3

7 0
3 years ago
At a constant pressure, 10 L of a gas at 546 K is cooled to 273 K
lisabon 2012 [21]

Answer:

5 L

Explanation:

Ideal gas law:

PV = nRT

If P, n, and R are constant, then:

n₁R/P₁ = n₂R/P₂

Using ideal gas law, we can rewrite this as:

V₁/T₁ = V₂/T₂

This is known as Charles' law.

Plugging in values:

10 L / 546 K = V / 273 K

V = 5 L

8 0
3 years ago
Please solve the Problem.
STatiana [176]

(a) For series circuit, current in 14 ohms = current in 72 ohms = 0.698 A

(b) Power loss in each series resistor, 14 ohms = 6.82 W and 72 ohms = 35.1 W.

(c) For parallel circuit, current in 14 ohms = 4.29 A and current in 72 ohms = 0.83 A

(d) Power loss in each parallel resistor, 14 ohms = 257.4 W and 72 ohms = 49.8 W.

<h3>Current in each series resistors</h3>

The total resistance = R1 + R2

                              R = 14 + 72 = 86 ohms

Current = V/R = 60/86 = 0.698 A

Since the resistors are in series, current in 14 ohms = current in 72 ohms = 0.698 A

<h3>Power loss in each series resistor</h3>

P = I²R

P(14 ohms) = (0.698)² x 14 = 6.82 W

P(72 ohms) = (0.698)² x 72 = 35.1 W

<h3>Current in each resistor for parallel arrangement</h3>

Total resistance, 1/R = 1/R1 + 1/R2

1/R = 1/14 + 1/72

1/R = 0.0853

R = 1/0.0853

R = 11.72

Total current in the circuit = V/R = 60/11.72 = 5.12 A

Current in 14 ohms = 60/14 = 4.29 A

Current in 72 ohms = 60/72 = 0.83 A

<h3>Power loss in each parallel resistor</h3>

P = IV

P(14 ohms) = (4.29) x 60 = 257.4 W

P(72 ohms) = 0.83 x 60 = 49.8 W

Learn more about current here: brainly.com/question/24858512

#SPJ1

5 0
2 years ago
An insect meanders across a sidewalk. The insect moves 15cm to the right, 10cm up the sidewalk and 8cm to the left. What is the
IRISSAK [1]

Answer:12.206 cm,\theta =54.99^{\circ}

Explanation:

Given

Insect walks 15 cm to the right

so its position vector isr_1=15i

Now it moves 10 cm up so its new position vector

r_2=15i+10j

Now it moves 8 cm left so its final position vector is

r_3=15\hat{i}+10\hat{j}-8\hat{i}=7\hat{i}+10\hat{j}

so its displacement is given by

|r_3|=\sqrt{7^2+10^2}=\sqrt{149}=12.206 cm

For direction, let \theta is the angle made by its position vector with x axis

tan\theta =\frac{10}{7}=1.428

\theta =54.99^{\circ}

8 0
3 years ago
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