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miskamm [114]
3 years ago
12

PLEASE ANSWER! DESPERATE! WILL MARK BRAINLIEST!!

Physics
1 answer:
Virty [35]3 years ago
7 0

Answer:

\boxed{energy} \to \: is \: the \: capacity \: for \: doing \: work. \\  \: energy \: can \: exist\: in \: vaious \: forms : such \: as \to \\  \boxed{thermal}\boxed{mechanical}\boxed{chemical}\boxed{solar}......etc.\\ its \to \: \boxed{ solar \: energy} : without \: solar \: energy \\  \: i \: dont \: think \: life \: on \: earth \: or \:  \\ other \:p lanetry \: bodies \: would  \: be \: possible. \\  \: solar \: energy \: from \: different \: stars \\  \: are \: responssible \: for \: warming \: of \: thier \: solar \: systems \\  \: and \:collectively \:  saves\: thier \: galaxies \: from \: being \:  \boxed{dark \: cold}.

Explanation:

♨Rage♨

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A golfer is on the edge of a 12.5 m bluff overlooking the 18th hole which is located 60 m from the base of the bluff. She launch
Lina20 [59]

Answer:

The ball impact velocity i.e(velocity right before landing) is 6.359 m/s

Explanation:

This problem is related to parabolic motion and can be solved by the following equations:

x=V_{o}cos \theta t----------------------(1)

y=y_{o}+V_{o} sin \theta t - \frac{1}{2}gt^{2}---------(2)

V=V_{o}-gt ----------------------- (3)

Where:

x = m is the horizontal distance travelled by the golf ball

V_{o} is the golf ball's initial velocity

\theta=0\° is the angle (it was  a horizontal shot)

t is the time

y is the final height of the ball

y_{o} is the initial height of the ball

g is the acceleration due gravity

V is the final velocity of the ball

Step 1: finding t

Let use the equation(2)

t=\sqrt{\frac{2 y_{o}}{g}}

t=\sqrt{\frac{2 (12.5 m)}{9.8 m/s^{2}}}

t=1.597s

Substituting (6) in (1):

67.1 =V_{o} cos(0\°) 1.597-------------------(4)

Step 2:  Finding V_{o}:

From equation(4)

67.1 =V_{o}(1) 1.597

V_0 = \frac{6.71}{1.597}

V_{o}=42.01 m/s (8)  

Substituting V_{o} in (3):

V=42.01 -(9.8)(1.597)

v =42 .01 - 15.3566  

V=26.359 m/s

5 0
3 years ago
a car slows down from 22 m/s to 3 m/s at a constant rate of 3.5 m/s squared. how many seconds are required before the car is tra
Stolb23 [73]

Answer:

9.05 s

Explanation

v=u+at

6 0
3 years ago
In what way could a random mutation provide an organism with an advantage? With a example please
saveliy_v [14]

Answer:

They are called beneficial mutations. They lead to new versions of proteins that help organisms adapt to changes in their environment. Beneficial mutations are essential for evolution to occur. They increase an organism's changes of surviving or reproducing, so they are likely to become more common over time.

Explanation:

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2 years ago
Which of the following is NOT a good way to reduce fuel consumption?
Sidana [21]

Answer:

Explanation:

d

4 0
3 years ago
Read 2 more answers
A ball is kicked from the top of a building with a velocity of 50 m/s and lands 165 m away from the base of the buildi
solniwko [45]

Answer:

32.3 m/s

Explanation:

The ball follows a projectile motion, where:

- The horizontal motion is a uniform motion at costant speed

- The vertical motion is a free fall motion (constant acceleration)

We start by analyzing the horizontal motion. The ball travels horizontally at constant speed of

v_x = 50 m/s

and it covers a distance of

d = 165 m

So, the total time of flight of the ball is

t=\frac{d}{v_x}=\frac{165}{50}=3.3 s

In order to find the vertical velocity of the ball, we have now to analyze its vertical motion.

The vertical motion is a free-fall motion, so the ball is falling at constant acceleration; therefore we can use the following suvat equation:

v_y = u_y +at

where

v_y is the vertical velocity at time t

u_y=0 is the initial vertical velocity

a=g=9.8 m/s^2 is the acceleration  of gravity (taking downward as positive direction)

Substituting t = 3.3 s (the time of flight), we find the final vertical velocity of the ball:

v=0 + (9.8)(3.3)=32.3 m/s

5 0
3 years ago
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