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miskamm [114]
3 years ago
12

PLEASE ANSWER! DESPERATE! WILL MARK BRAINLIEST!!

Physics
1 answer:
Virty [35]3 years ago
7 0

Answer:

\boxed{energy} \to \: is \: the \: capacity \: for \: doing \: work. \\  \: energy \: can \: exist\: in \: vaious \: forms : such \: as \to \\  \boxed{thermal}\boxed{mechanical}\boxed{chemical}\boxed{solar}......etc.\\ its \to \: \boxed{ solar \: energy} : without \: solar \: energy \\  \: i \: dont \: think \: life \: on \: earth \: or \:  \\ other \:p lanetry \: bodies \: would  \: be \: possible. \\  \: solar \: energy \: from \: different \: stars \\  \: are \: responssible \: for \: warming \: of \: thier \: solar \: systems \\  \: and \:collectively \:  saves\: thier \: galaxies \: from \: being \:  \boxed{dark \: cold}.

Explanation:

♨Rage♨

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A 2.0 kg bucket is attached to a horizontal ideal spring and rests on frictionless ice. You have a 1.0 kg mass
bogdanovich [222]

Answer:

x = A cos (w \sqrt{2y_{o}/g})

a) maximun  Ф= \sqrt{\frac{2}{3}  \frac{2 y_{o} }{g}  }

b) minimun     Ф = \frac{\pi }{2} - \sqrt{\frac{2}{3}  \frac{2 y_{o} }{g}  }

Explanation:

For this exercise let's use kinematics to find the time it takes for the mass to reach the floor

         y = y₀ + v₀ t - ½ g t²

   

as the mass is released from rest, its initial velocity is zero (vo = 0) and its height upon reaching the ground is zero (y = 0)

      0 = y₀ - ½ g t²

      t = \sqrt{2y_{o}/g}

The bucket-spring system has a simple harmonic motion, which is described by

     x = A cos wt

in this expression we assumed that the phase constant (Ф) is zero

let's replace the time

     x = A cos (w \sqrt{2y_{o}/g})

this is the distance where the system must be for the mass to fall into it.

a) The new system has a total mass of m ’= 3.0 kg, so its angular velocity changes

          w = \sqrt{k/m}

In the initial state

         w = \sqrt{k/2}

When the mass changes

         w ’= \sqrt{k/3}

the displacement in each case is

         x = A cos (wt)

for the new case

        x ’= A cos (w’t + Ф)

the phase constant is included to take into account possible changes due to the collision of the mass.

we see that this maximum expressions when the cosine is maximum

        cos (w´t + Ф) = 1

         w’t + Ф = 0

        Ф = -w ’t

        Ф = - \sqrt{k/3} \sqrt{2y_{o}/g}

       \sqrt{\frac{2}{3}  \frac{2 y_{o} }{g}  }

b) the function is minimun if

        cos (w’t + fi) = 0

        w’t + Ф = π / 2

        Ф = π / 2 - w ’t

        Ф = \frac{\pi }{2} - \sqrt{\frac{2}{3}  \frac{2 y_{o} }{g}  }

8 0
3 years ago
How much work is done on an object that is moved to acquire a displacement of 5 meters when 500 Newtons of force was exerted?​
grandymaker [24]

Answer:

2,500 Joules (J) or Newton Meter (N M)

Explanation:

Work = Force x Distance

The force in this equation is 500 Newtons. The distance (displacement) is 5 meters. Plug it into the equation above.

Work = 5m x 500n

Work = 2,500 Joules or Newton-Meters.

Therefore 2,500 Joules or Newton Meters of work is done on an object.

3 0
2 years ago
A golf ball strikes a hard, smooth floor at an angle of 28.2 ° and, as the drawing shows, rebounds at the same angle. The mass o
WITCHER [35]

Answer:

    I = 1.06886  N s

Explanation:

The expression for momentum is

          I = F t = Δp

therefore the momentum is a vector quantity, for which we define a reference system parallel to the floor

Let's find the components of the initial velocity

          sin 28.2 = v_y / v

          cos 28.2=  vₓ / v

          v_y = v sin 282

          vₓ = v cos 28.2

          v_y = 42.8 sin 28.2 = 20.225 m / s

          vₓ = 42.8 cos 28.2 = 37.72 m / s

since the ball is heading to the ground, the vertical velocity is negative and the horizontal velocity is positive, it can also be calculated by making

θ = -28.2

         v_y = -20.55 m / s

         v_x = 37.72 m / s

X axis

         Iₓ = Δpₓ = p_{fx} - p_{ox}

since the ball moves in the x-axis without changing the velocity, the change in moment must be zero

         Δpₓ = m v_{fx} - m v₀ₓ = 0

          v_{fx} = v₀ₓ

therefore

          Iₓ = 0

Y axis  

        I_y = Δp_y = p_{fy} -p_{oy}

when the ball reaches the floor its vertical speed is downwards and when it leaves the floor its speed has the same modulus but the direction is upwards

         v_{fy} = - v_{oy}

         Δp_y = 2 m v_{oy}

         Δp_y = 2 0.0260 (20.55)

         \Delta p_{y} = 1.0686 N s

the total impulse is

          I = Iₓ i ^ + I_y j ^

          I = 1.06886  j^ N s

7 0
2 years ago
Which three characteristics of an object are represented by a motion map?
Reptile [31]

Answer:

Last option: position, acceleration, velocity

Explanation:

Motion maps are generally used in Kinematics to visualize the object's position (normally with pictures of the object) at different times, and its state of motion with vectors indicating its velocity and its acceleration at those times.

7 0
3 years ago
Read 2 more answers
Explain why the internal energy of a solid increases when its heated at its melting point
snow_lady [41]
Because the molecules are vibrating. Also keep in mind that when a substance is a solid its molecules are tightly packed. When it is a liquid its molecules are less compact
6 0
3 years ago
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