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miskamm [114]
3 years ago
12

PLEASE ANSWER! DESPERATE! WILL MARK BRAINLIEST!!

Physics
1 answer:
Virty [35]3 years ago
7 0

Answer:

\boxed{energy} \to \: is \: the \: capacity \: for \: doing \: work. \\  \: energy \: can \: exist\: in \: vaious \: forms : such \: as \to \\  \boxed{thermal}\boxed{mechanical}\boxed{chemical}\boxed{solar}......etc.\\ its \to \: \boxed{ solar \: energy} : without \: solar \: energy \\  \: i \: dont \: think \: life \: on \: earth \: or \:  \\ other \:p lanetry \: bodies \: would  \: be \: possible. \\  \: solar \: energy \: from \: different \: stars \\  \: are \: responssible \: for \: warming \: of \: thier \: solar \: systems \\  \: and \:collectively \:  saves\: thier \: galaxies \: from \: being \:  \boxed{dark \: cold}.

Explanation:

♨Rage♨

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A wave with a large amplitude

a wave check

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Power is the product of_____.
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3 0
2 years ago
Please help me it's URGENT (#10 btw and also how do I solve for time​
Afina-wow [57]

Answer:

t = 12s

Explanation:

Given:

v-initial = 0 m/s

x = 360 m

a = 5.0 m/s^2

Solve:

x = (v-initial)t + 1/2(a*t^2)

360 = 0t + 1/2 (5.0t^2)

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5 0
2 years ago
A 14.0 gauge copper wire of diameter 1.628 mm carries a current of 12.0 mA . A) What is the potential difference across a 1.80 m
Serga [27]

Answer: a) 139.4 μV; b) 129.6 μV

Explanation: In order to solve this problem we have to use the Ohm law given by:

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Then we have:

for cooper R=1.71 *10^-8* 1.8/(0.001628)^2= 11.61 * 10^-3Ω

and for silver R= 1.58 *10^-8* 1.8/(0.001628)^2=10.80 * 10^-3Ω

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8 0
3 years ago
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<h3>Hope This Helps</h3>
6 0
2 years ago
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