Answer:
(9, -15)
Step-by-step explanation:
First, label the 2 equations:
-10x -6y= 0 -----(1)
-4x -6y= 54 -----(2)
(2) -(1):
(-4x -6y) -(-10x-6y)= 54 -0
-4x -6y -(-10x) -(-6y)= 54 (expand, simplify)
-4x -6y +10x +6y= 54 (expand)
10x -4x= 54 (simplify)
6x= 54
x=54 ÷6
x= 9
susbt. x=9 into (1):
-10(9) -6y=0 (subst. x=9 into -10x-6y=0)
-90= 6y (bring y term to the other side)
6y= -90
y= -90 ÷6
y= -15
Thus, the solution is (9, -15).
Answer:
d= bv + r
Treat it like you would a normal equation. Multiply by b and add r to isolate d.
Let denote the amounts (in liters) of the 20%, 30%, and 60% solutions used in the mixture, respectively.
The chemist wants to end up with 72 L of solution, so
while using twice as much of the 60% solution as the 30% solution, so
The mixture needs to have a concentration of 35%, so that it contains 0.35•75 = 26.25 L of pure acid. For each liter of acid solution with concentration , there is a contribution of liters of pure acid. This means
Substitute into the total volume and acid volume equations.
Solve for and . Multiply both sides of the second equation by 5 to get
By elimination,
so that
and
Answer:
200
Step-by-step explanation:
10*20=200.
I am not positive what you are asking but that is the answer I am able to give at this moment.
I hope I at least helped you. :)
6/1. Anything over 1 is itself