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NNADVOKAT [17]
3 years ago
7

class="latex-formula">
​
Mathematics
2 answers:
shtirl [24]3 years ago
8 0
9-7 is equal to 2
2/2 is equal to 1
1=m
Alex787 [66]3 years ago
3 0
When you are solving for m you want to seclude m on one side,

So start by subtracting 7 on both sides because you want to use inverse operations so since it’s positive use negative

2m = 2

Now since you use inverse operations you want the m by itself to since 2m is bound through multiplication use division so divide 2 on both sides and you’re left with

m = 1

You can check by filling m back into the equation

2(1) + 7 = 9

2 + 7 = 9

9 = 9

So it’s true
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Write an equation that is perpendicular to and 3x+y=3 whose y-intercept 5. Anyone please help me, no link just explain how to do
Liula [17]

Answer:

y = \frac{1}{3}x + 5

Step-by-step explanation:

By definition, two lines are perpendicular if and only if their slopes are negative reciprocals of each other:  m = - \frac{1}{m_{2} }, or equivalently, m_{1} * m_{2} = -1.

Given our linear equation  3x + y = 3  (or y = -3x + 3):

We can find the equation of the line (with a y-intercept of 5) that is perpendicular to y = -3x + 3 by determining the negative reciprocal of its slope, -3, which is \frac{1}{3}.

To test whether this is correct, we can take first slope,  m_{1} = -3,  and multiply it with the negative reciprocal slope m_{2} = \frac{1}{3} :

m_{1} * m_{2} = -1

-3 * \frac{1}{3}  = -1

Therefore, we came up with the correct slope for the other line, which is  \frac{1}{3}.

Finally, the y-intercept is given by (0, 5). Therefore, the equation of the line that is perpendicular to 3x + y = 3 is:

y = \frac{1}{3}x + 5

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