All categories

2 years ago

What is the value of x when the richter scale rating scale is 8.4?

Mathematics

1 answer:

Vsevolod [243]2 years ago

7 0

The value of x when the richter scale rating scale is 8.4 is 251188643.151

<h3>What is a richter scale?</h3>

A richter scale is a numerical scale that is used for expressing the magnitude of an earthquake in a geographical area

<h3>How the richter scale works?</h3>

The richter scale takes the amplitude of the earthquake's largest seismic as an input and calculate (and display) the magnitude of an earthquake in the geographical area using a logarithmic function

<h3>How to determine the value of x?</h3>

The formula of a richter scale is expressed as:

log(x) = n

Where n represents the scale rating of the scale

In this case, n = 8.4.

So, we have:

log(x) = 8.4

Express as an exponent

x = 10^8.4

Evaluate the exponent

x = 251188643.151

Hence, the value of x when the richter scale rating scale is 8.4 is 251188643.151

Read more about richter scale rating at

brainly.com/question/19799610

#SPJ1

You might be interested in

Lines a and b are parallel. What is the measure of angle b? Enter your answer in the box. b = ∘ Two horizontal lines the top lin

andrezito [222]

Answer:

It's 79 I took the test

Stay Alive ~ T∅P I-/

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Find the solution to the equation below.<br> 2x^2+3x-20=0

mariarad [96]

Answer:

x = -4, 5/2

Step-by-step explanation:

A quadratic can be solved may ways, including graphing, factoring, and the quadratic formula. You can also check possible answers by making use of the relationships between solutions and the coefficients.

A graph is attached. It shows the solutions to be -4 and 5/2.

When factored, the equation becomes ...

(2x -5)(x +4) = 0 . . . . . has solutions x=-4, x=5/2 (these make the factors zero)

Using the quadratic formula, the solutions of ax^2 +bx +c = 0 are found from ...

x = (-b±√(b²-4ac))/(2a)

x = (-3±√(3²-4(2)(-20))/(2(2)) = (-3±√169)/4 = {-16, +10}/4

x = {-4, 5/2}

For ax^2 +bx +c = 0, the solutions must satisfy ...

product of solutions is c/a = -20/2 = -10

Only the first and last choices have this product.

sum of solutions is -b/a = -3/2

Only the first choice (-4, 5/2) has this sum.

8 0

3 years ago

Bennett has 107 photographs to place in the school yearbook. He will put the same number of photos on each of the 13 pages. if h

HACTEHA [7]

Answer:

Step-by-step explanation: if he has 2 rows of four on each page and 13 pages 8 * 13 is 104 and 107 - 104 is 3

7 0

3 years ago

Read 2 more answers

Can someone please answer this question answer it correctly and show work please

mrs_skeptik [129]

Answer:

$1,216

Step-by-step explanation:

Costs for Handsome Homes fabric

Area (sq. ft.) Cost (dollars)

(x) (y)

250 475

500 950

750 1,420

1000 1,900

If you divide any y-value by its corresponding x-value, the quotient will be 1.9

This means that each square foot costs $1.90 at Handsome Homes

Discount Diggers = 20% per sq. ft. less than Handsome homes

Discount Diggers = $1.90 - 20%

Discount Diggers = $1.90(100 - 20%)

Discount Diggers = $1.90(0.8)

Discount Diggers = $1.52

Now that it is known how much 1 square foot of fabric costs at Discount Diggers, we need to find how much 800 square feet of fabric costs.

$1.52 = 1 sq. ft.

$1.52(800) = 800 sq. ft.

$1,216

800 square feet of landscape fabric at Discount Diggers costs $1,216

Hope this helps :)

5 0

3 years ago

There are three power plants [X, Y, Z] that at any given time each one either generates electricity or idles. Event A is that pl

insens350 [35]

We're told that

$P(A\cap B)=0.15$

$P(A\cup B)^C=0.06\implies P(A\cup B)=0.94$

$P(B\mid A)=P(B^C\mid A)=0.5$

where the last fact is due to the law of total probability:

$P(A)=P(A\cap B)+P(A\cap B^C)$

$\implies P(A)=P(B\mid A)P(A)+P(B^C\mid A)P(A)$

$\implies 1=P(B\mid A)+P(B^C\mid A)$

so that $B\mid A$ and $B^C\mid A$ are complementary.

By definition of conditional probability, we have

$P(B\mid A)=P(B^C\mid A)$

$\implies\dfrac{P(A\cap B)}{P(A)}=\dfrac{P(A\cap B^C)}{P(A)}$

$\implies P(A\cap B)=P(A\cap B^C)$

We make use of the addition rule and complementary probabilities to rewrite this as

$P(A\cap B)=P(A\cap B^C)$

$\implies P(A)+P(B)-P(A\cup B)=P(A)+P(B^C)-P(A\cup B^C)$

$\implies P(B)-[1-P(A\cup B)^C]=[1-P(B)]-P(A\cup B^C)$

$\implies2P(B)=2-[P(A\cup B)^C+P(A\cup B^C)]$

$\implies2P(B)=[1-P(A\cup B)^C]+[1-P(A\cup B^C)]$

$\implies2P(B)=P(A\cup B)+P(A\cup B^C)^C$

$\implies2P(B)=P(A\cup B)+P(A^C\cap B)\quad(*)$

By the law of total probability,

$P(B)=P(A\cap B)+P(A^C\cap B)$

$\implies P(A^C\cap B)=P(B)-P(A\cap B)$

and substituting this into $(*)$ gives

$2P(B)=P(A\cup B)+[P(B)-P(A\cap B)]$

$\implies P(B)=P(A\cup B)-P(A\cap B)$

$\implies P(B)=0.94-0.15=\boxed{0.79}$

8 0

3 years ago