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wlad13 [49]
3 years ago
7

Rename the number. 25,600=__________ hundreds

Mathematics
1 answer:
DENIUS [597]3 years ago
3 0
25,600=256 hundreds.
25600/100=256
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Write two perfect squares that each have a value greater than100 and less than 200
Trava [24]

Answer:

121, 144

Step-by-step explanation:

√121= 11

√144= 12

6 0
2 years ago
there are 12 teams in the jayhook hockey league each team plays every other team twice per season, once at home and once away. L
Gre4nikov [31]

Answer:

58

Step-by-step explanation:

As there are 12 teams in the league and each teams plays every other team twice per season. so, the total number of matches in the league will be 132.

let the matches won by home team = 'x'

given,

number of matches drawn = 34

matches won by the away team = x - 18

Now, according to the question,

⇒ total matches = matches drawn + matches won by home team + matches won by away team

⇒ 132 = 34 + x + x -18

⇒ x = 58

5 0
3 years ago
Why is dividing a fraction by 3 and then multiplying by 2 the same as multiplying by 2/3?
Tema [17]
It would be the same you would already be dividing by 3 because it’s the denominator and the numerator is 2
7 0
2 years ago
What is the absolute value of the complex number -4-√2
Zepler [3.9K]
|a+bi| = √(a² + b²)

-4-√2 i -> take a = -4 and b = -√2

|-4-√2 i| = √[ (-4)² + (<span>-√2)² ]
               = </span><span>√[ 16 + 2<span> ]
               </span></span><span>= √[ 18 ]</span> = <span>√[ 9 * 2 ]
               = 3√2
the absolute value is 3√2</span>

6 0
3 years ago
In a random sample of 30 people who rode a roller coaster one day, the mean wait time is 46.7 minutes with a standard deviation
Rainbow [258]

Answer: C. (29,\ 37.8)

Step-by-step explanation:

The confidence interval for difference of two population mean is given by :-

\overline{x}_1-\overline{x}_2\pm z_{\alpha/2}\sqrt{\dfrac{s_1^2}{n_1}+\dfrac{s_2^2}{n_2}}

Given : Level of significance : 1-\alpha:0.99

Then , significance level : \alpha: 1-0.99=0.01

Critical value : z_{\alpha/2}=z_{0.005}=2.576

n_1=30\ ;\ n_2=50\\\\\overline{x}_1=46.7\ ;\ \overline{x}_2=13.3\\\\s_1=9.2\ ;\ s_2=1.9

46.7-13.3\pm(2.576)\sqrt{\dfrac{9.2^2}{30}+\dfrac{1.9^2}{50}}\approx33.4\pm4.38=(29.02\ ,37.78)\approx(29,\ 37.8)

Hence,  a 99% confidence interval for the difference between the mean wait times of everyone who rode both rides (29,\ 37.8)

5 0
3 years ago
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