2 years ago

Give an example of a situation in which you would describe an object's position in one dimension two dimensions three dimension

1 answer:

8 0

One dimension:
I'm waiting patiently for the elevator. What floor is it on now ?

Two dimensions:
What's the address of your house ?
Where do you want this picture hung on your bedroom wall ?
Where is the Maersk Skokie supertanker located today ?
Where are your rooks and pawns on the chessboard ?

Three dimensions:
I'm waiting at the airport for my brother to arrive.
He's on Flight AC3715.
Where is the flight located right now ?

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IRISSAK [1]

Answer:

Explanation:

Force I think

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2 years ago

Since all stars begin their lives with the same basic composition, what characteristic most determines how they will differ?

Dafna1 [17]

4. Mass they are formed with

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3 years ago

A reaction mixture in a 3.67 L flask at a certain temperature initially contains 0.763 g H2 and 96.9 g I2, At equilibrium, the f

Alexxandr [17]

Answer:

13 530 482

Explanation:

H2 + I2 ------> 2HI

start (mol) 0.3785 0.3818 0

change (mol) -0.3534 -0.3534 +0.7067

equilibrium (mol) 0.0251 0.0284 0.7067

concentra (mol/L) 0.0068 0.0077 0.1926

$K_{c} = \frac{0.1926^{2}}{0.0068^{2}*0.0077^{2} } = 13530482$

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2 years ago

Two positive charge spheres, the spheres are separated by 0.40 m. The charge on the first sphere is 100 microcoulombs and the

agasfer [191]

Answer: 168.75 N

Explanation:

first, let's convert microcoulombs to coulombs

q1 = 1e-4 C

q2 = 3e-5 C

r = 0.4 m

then use the equation Fe = $\frac{kq_{1} q_{2}}{r^{2} }$

plug in values --> F = (9e9*1e-4*3e-5)/(0.4)^2

F = 168.75 N

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6 months ago

A swimming pool has the shape of a box with a base that measures 30 m by 12 m and a uniform depth of 2.2 m. How much work is req

Alex777 [14]

Answer:

853776 J

Explanation:

The work-energy needs to pump water out of the pool is the product of the weight of water and distance h

E = Wh = mgh

Since water mass is a body of water we can treat it as the product of density 1000kg/m3 and volume, which is the product of base area and uniform height h

$m = \rho V = \rho \int\limits^{2.2}_0 {A} \, dh$

Therefore:

$E = mgh = g\rho A\int\limits^{2.2}_0 {h} \, dh\\E = 9.8*1000*30*12[h^2/2]^{2.2}_0 = 1764000(2.2^2 - 0^2) = 853776 J$

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2 years ago