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4 years ago

How does Newton describe the dependence of acceleration of a body on its mass and the net applied force?

Physics

2 answers:

Maurinko [17]4 years ago

8 0

Answer:

Explanation:

USATESTPREP

neonofarm [45]4 years ago

7 0

Answer:

The acceleration of the object are directly proportional to the force applied

Explanation:

As per Newton's 2nd law of motion we know that

rate of change in momentum of the object is directly proportional to the net force on it

so here we will have

$F = \frac{dp}{dt}$

here we know that momentum is the product of mass and velocity

so we will have

P = mv

now we have

$\frac{dp}{dt} = m\frac{dv}{dt} = ma$

so we have

F = ma

so here we can say

The acceleration of the object are directly proportional to the force applied

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In the late 19th century, great interest was directed toward the study of electrical discharges in gases and the nature of so-ca

gizmo_the_mogwai [7]

Answer:

A) He finds the same value of q / m for different materials , B) y = ½ (q / m) E L² / v₀ₓ² , C) v = E / B , D) B = 2.13 10⁻⁶ T, E) For the first part I have two off-center points., For the second part I can center one point but the other is off center

Therefore the third statement is correct

Explanation:

Part A

Thomson's experiments are the first proof that the atoms that until now were considered indivisible were constituted by different elements, in these experiments Thomson himself the ratio q / m of several cathodes and always found the same value, which allowed to establish that In atoms there are two types of particles, some of which are mobile and others are still.

When examining his statements the correct one is: He finds the same value of q / m for different materials

Part B

For this part let's use Newton's second law

F = ma

q E = m a

a = q / m E

We use the kinematic relationship

y = voy t - ½ to t²

x = v₀ₓ t

The initial vertical velocity of electrons is zero

y = ½ a (x / v₀ₓ)²

We replace

y = ½ (q / m) E L² / v₀ₓ²

Part C

If there is no deflection, the electric and magnetic forces are the same and in the opposite direction

Fm = Fe

q v B = q E

v = E / B

Part D

We replace

y = ½ (q / m) E L² / (E / B)²

y = ½ (q / m) L² B² / E

If we do not want any deflection the magnetic field has to return the electrons the amount that they lower y = -4.12 cm

-4.12 10⁻² = ½ q / m 0.12² B² / 1.1 10³

-16.97 10⁻⁴ = 6.54 10⁻³ B² q / m

B² = -2.59 10⁻¹ q / m

q / m = -1.758 10¹¹ C/ kg

B = √ 0.259 1.758 10¹¹ = √ 4.55 10⁻¹²

B = 2.13 10⁻⁶ T

Part E

As the charge that the two particles is different

For the first part I have two off-center points.

For the second part I can center one point but the other is off center

Therefore the third statement is correct

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3 years ago

A direct injection (DI) fuel injector system sprays high-pressure fuel, up to _______ psi, into the combustion chamber as the pi

Vika [28.1K]

The answer is not 65. ya moms a hooch

3 0

4 years ago

Read 2 more answers

D=? V=100mL M=1.5kg=___g

Nana76 [90]

If you go to a website known as 'Wolfram' and type in the question they should be able to answer it. It's basically a very smart calculator. I'd add a link but I don't want to seem like I'm advertising, and it's against Brainly rules.

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4 years ago

A bird flying 5.0 m overhead sees me drop it, and starts to dive straight down towards the bread the instant I release it. She c

gladu [14]

Answer:

Explanation:

muntiply the 5.0.3.0 ,you will get ans

5 0

3 years ago

A coin is dropped from a height and reaches the ground in 2 seconds. Neglecting air resistance, from what height (in meters) was

Kamila [148]

Answer:

Coin is dropped from a height of 19.62 m

Explanation:

We have given time t = 2 sec

As coin is drop means its initial velocity u = 0 m/sec

We have to find the height from which coin is dropped

From second equation of motion we know that

$h=ut+\frac{1}{2}gt^2$

So height $h=0\times2+\frac{1}{2}\times 9.81\times 2^2=19.62m$

So coin is dropped from a height of 19.62 m

3 0

3 years ago