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4 years ago

7

Define limitations in the operation conditions of a pn junction

1 answer:

suter [353]4 years ago

6 0

Answer:

Such limitations are given below.

Explanation:

Each pn junction provides limited measurements of maximum forwarding current, highest possible inversion voltage as well as the maximum output level.
If controlled within certain adsorption conditions, the pn junction could very well offer satisfying performance.
In connector operation, the maximum inversion voltage seems to be of significant importance.

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List several examples of applied force, normal force, and friction that you’ve observed in your life.

grandymaker [24]

applied forces would be push for example.

normal forces would seem to be a force such as gravity.

friction for example when you try to slide on carpet but the fabric or whatever its made of stops you.

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3 years ago

With fuel prices for combustible engine automobiles increasing, researchers and manufacturers have given more attention to the c

Alinara [238K]

Answer:

Then the difference of weight between the two cars are:

Δw = 14210 - 5292 = 8918 N

Explanation:

An object's weigh due to the gravitational attraction force of the earth is:

w = mg

Where: m is the object's mass

g is the gravitational acceleration in the surface earth

g = 9.8 m/s2

The the ultralight car's weight is:

$w_{uc} = (540)(9.8)$

$w_{uc} = 5292 N$

And the Honda Accord's weight is:

$w_{HA} = (1450)(9.8)$

$w_{HA} = 14210 N$

Then the difference of weight between the two cars are:

Δw = 14210 - 5292 = 8918 N

4 0

3 years ago

Consider what will happen when a bar magnet is pushed toward the coil. when the coil "feels" the changing magnetic field caused

notka56 [123]

The question just basically explained what happens

4 0

4 years ago

Absorbance measurements in the range of a = 0.3-2 are considered the most accurate. why would absorbance measurements of 0.05 an

zhenek [66]

Please provide the choices to select the possible choices.

6 0

3 years ago

A vacuum cleaner produces sound with a measured sound level of 75.0 dB. (a) What is the intensity of this sound in W/m2? W/m2 (b

jonny [76]

Answer:

Part a)

$I = 3.16 \times 10^{-5} W/m^2$

Part b)

$P_o = 0.162 Pa$

Explanation:

Part a)

Level of sound = 75 dB

now we know that

$L = 10 Log\frac{I}{I_0}$

here we know that

$I_0 = 10^{-12} W/m^2$

now we have

$75 = 10 Log(\frac{I}{10^{-12}})$

$I = 3.16 \times 10^{-5} W/m^2$

Part b)

Intensity of sound wave is given as

$I = \frac{1}{2}\rho A^2\omega^2 c$

here we know that

$A = \frac{P_o}{Bk}$

so we have

$I = \frac{1}{2}\rho(\frac{P_o}{Bk})^2\omega^2 c$

$I = \frac{1}{2}\rho P_o^2 \frac{c^3}{B^2}$

now we know

$\rho = 1.2 kg/m^3$

$c = 340 m/s$

$B = 1.4 \times 10^5 Pa$

now we have

$3.16 \times 10^{-5} = \frac{1}{2}(1.2)P_o^2\frac{340^3}{(1.4\times 10^5)^2}$

$P_o = 0.162 Pa$

5 0

3 years ago