These are two separate problems: in the first we will have to substitute in a new value for x into the original equation and in the second we will manipulate the preexisting equation for f(x).
To begin, we will sub in f(x/3). To do this, we will substitute each variable x in the equation (in this case there is only one) with x/3, and then simplify the resulting equation.
f(x) = 6x - 18
f(x/3) = 6(x/3) - 18
To simplify, we should distribute the 6 on the right side of the equation.
f(x/3) = 6x/3 - 18
Now, we can divide the first term on the right side to finalize our simplification.
f(x/3) = 2x -18
Secondly, we are asked to find f(x)/3. To do this, we will take our original value for f(x), and then simplify divide that entire function by 3.
f(x) = 6x - 18
f(x)/3 = (6x-18)/3
This means that we must divide each term of the binomial by 3, so we are really computing
f(x)/3 = 6x/3 - 18/3
We can simplify by dividing both of the terms.
f(x)/3 = 2x - 6
Therefore, your answer is that f(x/3) = 2x - 18, but f(x)/3 = 2x - 6. It is important to recognize that these are two similar, yet different, answers.
Hope this helps!
My answer -
-5x^3+4x^2-5x
P.S
Have an AWESOME!!! LBGT Day :)
Square Root of 8 to the nearest tenth, means to calculate the square root of 8 where the answer should only have one number after the decimal point.
Here are step-by-step instructions for how to get the square root of 8 to the nearest tenth:
Step 1: Calculate
We calculate the square root of 8 to be:
√8 = 2.82842712474619
Step 2: Reduce
Reduce the tail of the answer above to two numbers after the decimal point:
2.82
Step 3: Round
Round 2.82 so you only have one digit after the decimal point to get the answer:
2.8
To check that the answer is correct, use your calculator to confirm that 2.82 is about 8.
Answer:
The answer is option 4.
Step-by-step explanation:
As there is a <em>M</em><em>o</em><em>d</em><em>u</em><em>l</em><em>u</em><em>s</em><em> </em><em>s</em><em>i</em><em>g</em><em>n</em><em> </em>so the answer will be always positive.
e.g
|1.2| = 1.2
|-5.6| = 5.6 (always interested in the positive value)
