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Lerok [7]
3 years ago
9

What is the answer for 5 1-= - +d6 3​

Mathematics
1 answer:
givi [52]3 years ago
5 0

Answer:

D=5/2. 5 over 2

Step-by-step explanation:

Cross multiply and solve for D

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Use the Pythagorean Theorem to solve for the missing side length. Round to the nearest tenth if necessary.
Ede4ka [16]

Answer:

B= 6

Step-by-step explanation:

pythagorean theorem formula is a² + b² = c²

so: 8² + b² = 10²

then: 64 + b² = 100

subtract 64 from both sides to get b²= 36

square root 36 and you get 6 for b

answer: B= 6

8 0
3 years ago
A recipe for 40 biscuits uses 2 cups of biscuit mix. How many biscuits are made from 1 cup of biscuit mix?​
In-s [12.5K]

Answer:

20 biscuits are made from 1 cup of biscuit mix.

Step-by-step explanation:

Divide 40 by 2 to get the unit rate, which is 20.

Hope this Helps!

5 0
3 years ago
Read 2 more answers
Kim makes a bar graph to record votes for the choice of a class pet.Each grid line represents 4 votes.Fish got 10 votes.The bar
rosijanka [135]

Answer: they  got 40 votes

Step-by-step explanation:

because 10+10+10+10 eqauls 40 yw friend follow me on tiktok @tayleerosee

8 0
3 years ago
Fran has a plank of wood 4.65 meters long. She wants to cut it into pieces 0.85 meters long. How many pieces of wood that length
DochEvi [55]
5 pieces. 4.65÷0.85=5. so u divide and ur answer is 5
3 0
3 years ago
How do I solve this?
Sonbull [250]

The question is somewhat poorly posed because the equation doesn't involve <em>θ</em> at all. I assume the author meant to use <em>x</em>.

sec(<em>x</em>) = csc(<em>x</em>)

By definition of secant and cosecant,

1/cos(<em>x</em>) = 1/sin(<em>x</em>)

Multiply both sides by sin(<em>x</em>) :

sin(<em>x</em>)/cos(<em>x</em>) = sin(<em>x</em>)/sin(<em>x</em>)

As long as sin(<em>x</em>) ≠ 0, this reduces to

sin(<em>x</em>)/cos(<em>x</em>) = 1

By definition of tangent,

tan(<em>x</em>) = 1

Solve for <em>x</em> :

<em>x</em> = arctan(1) + <em>nπ</em>

<em>x</em> = <em>π</em>/4 + <em>nπ</em>

(where <em>n</em> is any integer)

In the interval 0 ≤ <em>x</em> ≤ 2<em>π</em>, you get 2 solutions when <em>n</em> = 0 and <em>n</em> = 1 of

<em>x</em> = <em>π</em>/4   <u>or</u>   <em>x</em> = 5<em>π</em>/4

5 0
3 years ago
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