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poizon [28]
3 years ago
14

Ms. Anastasopoulos has 30 students. 4/5 of the students have pets. OF the students who have pets, 2/3 of them have a dog as a pe

t. What fraction of the students have a pet that is a dog?
Mathematics
1 answer:
Lena [83]3 years ago
6 0

Answer:

16

Step-by-step explanation:

since 4/5 have a pet, you would divide by 5.

30÷5=6

but since only 4 have a pet, you would multiply that by 4 to get 4/5

6×4=24

24 students have pets

now you would divide by 3, as 2/3 have a dog

24÷3=8

but only 2/3 have dog, so you would multiply by 2

8×2=16

I'm sure there is a simpler way but this is how I would do it.

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Effectus [21]
Your slope of this graph is: 4/3x
7 0
3 years ago
20. What is the value of y in the algebraic
Dennis_Churaev [7]

Answer: 17/7

Step-by-step explanation: Step 1: Simplify both sides of the equation. y+4/15 + 2y−5/5 = 2/5 1/15 y+ 4/15 + 2/5 y+−1= 2/5 (Distribute) ( 1/15 y+ 2/5 y)+( 4/15 +−1)= 2/5 (Combine Like Terms) 7/15 y+ −11/15 = 2/5 7/15 y+ −11/15 = 2/5 Step 2: Add 11/15 to both sides. 7/15 y+ −11/15 + 11/15 = 2/5 + 11/15 7 15 y= 17/15

7 0
3 years ago
If mAGF = mBGC = mDGC = mEGF = 70°, what is mAGB?<br> A.40° <br> B.70° <br> C.110° <br> D.35°
Tresset [83]
B it's going to work
7 0
3 years ago
Kaliska is jumping rope. The vertical height of the center of her rope off the ground R(t) (in cm) as a function of time t (in s
xz_007 [3.2K]

Answer:

R (t) = 60 - 60 cos (6t)

Step-by-step explanation:

Given that:

R(t) = acos (bt) + d

at t= 0

R(0) = 0

0 = acos (0) + d

a + d = 0 ----- (1)

After \dfrac{\pi}{12} seconds it reaches a height of 60 cm from the ground.

i.e

R ( \dfrac{\pi}{12}) = 60

60 = acos (\dfrac{b \pi}{12}) +d --- (2)

Recall from the question that:

At t = 0, R(0) = 0 which is the minimum

as such it is only  when a is  negative can acos (bt ) + d can get to minimum at t= 0

Similarly; 60 × 2 = maximum

R'(t) = -ab sin (bt) =0

bt = k π

here;

k  is the integer

making t the subject of the formula, we have:

t = \dfrac{k \pi}{b}

replacing the derived equation of k into R(t) = acos (bt) + d

R (\dfrac{k \pi}{b}) = d+a cos (k \pi) = \left \{ {{a+d  \ for \ k \ odd} \atop {-a+d \ for k \ even}} \right.

Since we known a < 0 (negative)

then d-a will be maximum

d-a = 60  × 2

d-a = 120 ----- (3)

Relating to equation (1) and (3)

a = -60 and d = 60

∴ R(t) = 60 - 60 cos (bt)

Similarly;

For R ( \dfrac{\pi}{12})

R ( \dfrac{\pi}{12}) = 60 -60 \ cos (\dfrac{\pi b}{12}) =60

where ;

cos (\dfrac{\pi b}{12}) =0

Then b = 6

∴

R (t) = 60 - 60 cos (6t)

7 0
3 years ago
Your class has 18 students. Exactly 23
Rama09 [41]

Answer:

Sample model as the picture attached, which shows 2/3 of 18 are circled.

Step-by-step explanation:

Here is the correct question: Your class has 18 students. Exactly 2/3

of them say that, out of all their subjects, they like science the most. Which model shows 2/3  of 18 circled?

Given: Total number of student is 18.

           2/3 of the total students like science the most.

Now, calculating the number students like the science the most.

∴ Number of students who like the science most= \frac{2}{3} \times 18= 12 \ students

12 students like the science most out of total students.

Sample model are shown in the picture attached, where out of 18 students only 12 are inside the circle to show they like science the most.

8 0
3 years ago
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