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3 years ago

True or false the measures of an exterior angle and the adjacent interior angle add up to 360 because they form a linear pair

2 answers:

7 0

THe given statement is " the measures of an exterior angle and the adjacent interior angle add up to 360 because they form a linear pair " .

And in a linear pair, the sum of the measures of exterior angle and adjacent interior angle is 180.

But in the statement, it is given that the sum is 360 degree.

So the given statement is false .

gavmur [86]3 years ago

7 0

The answer is False

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Find the profit % if selling price is Rs 130 and profit is Rs5

Ad libitum [116K]

Answer:

3.85 % to 2 decimal places

Step-by-step explanation:

If you have Rs5 profit it means that you have sold it for 135

Do 5 / 130

Then times the answer by 100 *100

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3 years ago

Read 2 more answers

Please answer this fast in two minutes now

Anuta_ua [19.1K]

Answer:

Step-by-step explanation:

from cosines theorem:

t² = 11² + 14² - 2•11•14•cos87°

t² = 121 + 196 + 308•0.05236

t² = 333.12688

t = √333.12688

t = 18.2517... ≈ 18.3

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3 years ago

Toretto and O’Conner graphed two different quadratic functions in vertex form. Toretto graphed f(x)=(x+3)^2+1 and O’Conner graph

Len [333]

Yo sup??

By observing the graph we can say that minimum value of Toretto graph occurs at x=-3

whereas the minimum value of OConner graph occurs at x=3 .

In the given figure the minimum value is at x=3

therefore OConner is correct because the vertex is (3,1)

Hope this helps

5 0

2 years ago

Is the ratio 25 to 16 proportional to the ratio 5 to 4

Nutka1998 [239]

No? I'm pretty sure it wouldn't be because 25 to 16 and then 5 to 4 if you multiplied by 5 it would be 25 to 20 so no.

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2 years ago

Determine the equation of quadratic function represented by the table of value below.

Svetllana [295]

Answer:

Step-by-step explanation:

The general rule for the quadratic function is

$y=ax^2+bx+c$

Use the data from the table:

$y(0)=6\Rightarrow 6=a\cdot 0^2+b\cdot 0+c\\ \\y(1)=4\Rightarrow 4=a\cdot 1^2+b\cdot 1+c\\ \\y(-1)=10\Rightarrow 10=a\cdot (-1)^2+b\cdot (-1)+c$

We get the system of three equations:

$\left\{\begin{array}{l}c=6\\ \\a+b+c=4\\ \\a-b+c=10\end{array}\right.$

From the first equation

$c=6,$ then

$\left\{\begin{array}{l}a+b=-2\\ \\a-b=4\end{array}\right.$

Add these two equations:

$a+b+a-b=-2+4\\ \\2a=2\\ \\a=1$

So,

$b=-2-a=-2-1=-3$

The quadratic function is

$y=1\cdot x^2-3x+6\\ \\y=x^2-3x+6$

6 0

2 years ago