Answer:
Well since there aren't any specifics all you can be given is an equation on how to solve it, if a box has 6 sides and it's a cube then it will just be L*W=A then multiply that area by 6, that gives you the full surface area and if you want it for 150 boxes then just multiply whatever you got for the surface area by 150. It will be different if it's a rectangular box though, with that you must solve the surface area for 3 different pieces and multiply them all by 2 then add them all up and you get the surface area of that shape, then you multiply by 150 and that's your answer.
Answer:
Let's simplify step-by-step.
34(5a−16)−13(6a−3)
Distribute:
=(34)(5a)+(34)(−16)+−2a+1
=154a+−12+−2a+1
Combine Like Terms:
=154a+−12+−2a+1
=(154a+−2a)+(−12+1)
=74a+−11
Answer:
=74a−11
Answer:
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15
Step-by-step explanation:
1 2 33
Answer:
probability that all of the sprinklers will operate correctly in a fire: 0.0282
Step-by-step explanation:
In order to solve this question we will use Binomial probability distribution because:
- In the question it is given that the sprinklers activate correctly or not independently.
- The number of outcomes are two i.e. sprinklers activate correctly or not.
A binomial distribution is a probability of a success or failures outcomes in an repeated multiple or n times.
Number of outcomes of this distributions are two.
The formula is:
b(x; n, P) = 
b = binomial probability also represented as P(X=x)
x =no of successes
P = probability of a success on a single trial
n = no of trials
is calculated as:
= n! / x!(n – x)!
= 10! / 10!(10-10)!
= 1
According to given question:
probability of success i.e. p = 0.7 i.e. probability of a sprinkler to activate correctly.
number of trials i.e. n = 10 as number of sprinklers are 10
To find: probability that all of the sprinklers will operate correctly in a fire
X = 10 because we have to find the probability that "all" of the sprinklers will operate correctly and there are 10 sprinklers so all 10 of them
So putting these into the formula:
P(X=x) = 
= C₁₀,₁₀ * 0.7¹⁰ * (1-0.7)¹⁰⁻¹⁰
= 1 * 0.0282 * (0.3) ⁰
= 1 * 0.0282 * 1
P(X=x) = 0.0282