F(x)=5x^2+3x^3+9x+1 is a _________polynomial constant linear quadratic cubic

Two people share £350 in the ratio 1 : 6. Calculate each share.

EleoNora [17]

Answer:

£50 and £300

Step-by-step explanation:

Sum the parts of the ratio 1 + 6 = 7 parts

Divide the amount by 7 to find the value of one part of the ratio

£350 ÷ 7 = £50 ← value of 1 part of ratio

Hence

1 person receives £50

the other person receives 6 × £50 = £300

6 0

2 years ago

Write an expression to represent the total cost of paint at a rate of $5.75 per ft.? to paint a triangular-shaped mural where th

ASHA 777 [7]

Answer:

C($)= (x²/2 +11x)5.75

Step-by-step explanation:

Let's assume the height= x

The base= x+22

Area= 1/2(base*height).

Area= 1/2((x+22)(x))

Area= x²/2 +11x

Cost per ft= $5.75

Cost for painting the triangular mural C

C($)= (x²/2 +11x)5.75

7 0

2 years ago

How do change 30/8 in to a mixed number

sashaice [31]

Make the numerator be the sum of a multiple of the denominator and a remainder...

30/8 is equal to:

(24+6)/8 is equal to

24/8+6/8

3+6/8

3 3/4

5 0

3 years ago

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Divide the fractions and simplify the answer 60 / 2 2/3

balu736 [363]

2 2/3 as a decimal is 2.66666667. 60 divided by 2.66666667 is 22.5.
As a fraction, the answer will be 22 5/10

Please mark my answer as the brainliest answer, I'd really appreciate it, thanks!

6 0

2 years ago

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In the game of blackjack played with one deck, a player is initially dealt 2 different cards from the 52 different cards in the

Volgvan

Answer:

$P =4.83\%$

Step-by-step explanation:

First we calculate the number of possible ways to select 2 cards an ace and a card of 10 points.

There are 4 ace in the deck

There are 16 cards of 10 points in the deck

To make this calculation we use the formula of combinations

$nCr=\frac{n!}{r!(n-r)!}$

Where n is the total number of letters and r are chosen from them

The number of ways to choose 1 As is:

$4C1 = 4$

The number of ways to choose a 10-point letter is:

$16C1 = 16$

Therefore, the number of ways to choose an Ace and a 10-point card is:

$4C1 * 16C1 = 4 * 16 = 64$

Now the number of ways to choose any 2 cards from a deck of 52 cards is:

$52C2 =\frac{52!}{2!(52-2)!}$

$52C2 = 1326$

Therefore, the probability of obtaining an "blackjack" is:

$P = \frac{4C1 * 16C1}{52C2}$

$P = \frac{64}{1326}$

$P = \frac{32}{663}$

$P =0.0483$

$P =4.83\%$

4 0

2 years ago

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