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melamori03 [73]
3 years ago
6

1. If 22.5 L of nitrogen at 734 mm Hg are compressed to 702 mm Hg at constant

Chemistry
1 answer:
Alika [10]3 years ago
8 0

Answer:

The answer to your question is   V2 = 23.52 l

Explanation:

Data

Volume 1 = V1 = 22.5 l

Pressure 1 = P1 = 734 mmHg

Volume 2 = V2 = ?

Pressure 2 = 702 mmHg

Process

To solve this problem use Boyle's law.

                      P1V1 = P2V2

-Solve for V2

                          V2 = P1V1 / P2

-Substitution

                          V2 = (734 x 22.5) / 702

-Simplification

                           V2 = 16515 / 702

-Result

                           V2 = 23.52 l

-Conclusion

If we diminish the pressure, the volume will be higher.

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the gas left in an used aerosol can is at a pressure of 103 kPa at 25 degrees celsius if this can be thrown into fire what is th
Rainbow [258]
Hello!

The pressure of the gas when it's temperature reaches 928 °C is 3823,36 kPa

To solve that we need to apply Gay-Lussac's Law. It states that the pressure of a gas when the volume is left constant (like in the case of a sealed container like an aerosol can) is proportional to temperature. This is the relationship derived from this law that we use to solve this problem:

P2= \frac{P1}{T1}*T2= \frac{103 kPa}{25}*928=3823,36 kPa

Have a nice day!
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3 years ago
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A nitrox ii gas mixture for scuba diving contains oxygen gas at 53 atm and nitrogen gas at 94 atm . what is the total pressure,
Alina [70]

Answer: The total pressure will be 1,11,720 torr.

Explanation:

Partial pressure of nitrogen gas.p_{N_2}=53 atm=53\times 760 torr= 40,280 torr (1atm = 760 torr)

Partial pressure of oxygen gas,p_{O_2}=94 atm=94\times 760 torr=71,440 torr

Total pressure, in torrs, of the scuba gas mixture = 40280 + 71440 torr =111,720 torr

Hence , the total pressure in scuba gas mixture is 111,720 torr.

6 0
4 years ago
Which change does an increase in heat energy cause?
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Answer:

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Explanation:

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Answer:

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In order to calculate how much heat is needed to raise the temperature you need to use the formula q =mass x specific heat x (final temperature- initial temperature) where q represents heat being absorbed or released. Before you begin you would convert kg to g because the specific heat is measure in g. So you would set up the equation as q = 358 g x .092 x (60-23 degrees Celsius) which would give you 1218.6
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