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vodka [1.7K]
2 years ago
6

What is light?

Chemistry
1 answer:
xxTIMURxx [149]2 years ago
7 0
1. A wave of vibrating electric and magnetic energy

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If the pOH of a cesium hydroxide solution is known to be 4.00. what is the (OH)? *Please round your answer to the appropriate nu
Snowcat [4.5K]

Answer:

i going to be aniston i would say take a gess

4 0
2 years ago
Empirical formula of a compound composed of 32.1 g potassium (k) and 6.57 g oxygen (o)?
tester [92]

The empirical formula is K₂O.

The empirical formula is the <em>simplest whole-number ratio</em> of atoms in a compound.

The <em>ratio of atom</em>s is the same as the <em>ratio of moles</em>.

So, our job is to calculate the <em>molar ratio</em> of K to O.

Step 1. Calculate the <em>moles of each element </em>

Moles of K = 32.1 g K × (1 mol K/(39.10 g K =) = 0.8210 mol K

Moles of O = 6.57 g O × (1 mol O/16.00 g O) = 0.4106 mol 0

Step 2. Calculate the <em>molar ratio of each elemen</em>t

Divide each number by the smallest number of moles and round off to an integer

K:O = 0.8210:0.4106 = 1.999:1 ≈ 2:1

Step 3: Write the <em>empirical formula </em>

EF = K₂O

5 0
3 years ago
How to tell the difference between polar and nonpolar covalent bonds?
NemiM [27]
You need to look at the electronegativity and decide wheter the difference of both of the numbers are significant enough to form a polar bond
3 0
3 years ago
What determines which element an atom is?
Lana71 [14]
C) number of protons.
4 0
3 years ago
Read 2 more answers
3. In a typical titration experiment a student titrates a 5.00 mL sample of formic acid (HCOOH), a monoprotic organic acid, with
ira [324]

Answer:

2.893 x 10⁻³ mol NaOH

[HCOOH] = 0.5786 mol/L

Explanation:

The balanced reaction equation is:

HCOOH + NaOH ⇒ NaHCOO + H₂O

At the endpoint in the titration, the amount of base added is just enough to react with all the formic acid present. So first we will calculate the moles of base added and use the molar ratio from the reaction equation to find the moles of formic acid that must have been present. Then we can find the concentration of formic acid.

The moles of base added is calculated as follows:

n = CV = (0.1088 mol/L)(26.59 mL) = 2.892992 mmol NaOH

Extra significant figures are kept to avoid round-off errors.

Now we relate the amount of NaOH to the amount of HCOOH through the molar ratio of 1:1.

(2.892992 mmol NaOH)(1 HCOOH/1 NaOH) = 2.892992 mmol HCOOH

The concentration of HCOOH to the correct number of significant figures is then calculated as follows:

C = n/V = (2.892992 mmol) / (5.00 mL) = 0.5786 mol/L

The question also asks to calculate the moles of base, so we convert millimoles to moles:

(2.892992 mmol NaOH)(1 mol/1000 mmol) = 2.893 x 10⁻³ mol NaOH

7 0
3 years ago
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