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vodka [1.7K]
3 years ago
6

What is light?

Chemistry
1 answer:
xxTIMURxx [149]3 years ago
7 0
1. A wave of vibrating electric and magnetic energy

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How many moles of CO2 are formed from 3.0 mol of C2H2
PilotLPTM [1.2K]

Answer:

50.0 moles C02

Explanation:

First write down the CORRECTLY balanced equation. NOTE: The equation you provide is incorrect.

2C2H2(g) + 5O2(g) ==> 4CO2(g) + 2H2O(g)  CORRECT EQUATION

Next, look at the stoichiometric ratio of C2H2 to CO2.  You can see it is 2 moles C2H2 produces 4 moles CO2.

Thus, 25.0 moles C2H2 x 4 moles CO2/2 moles C2H4 = 50.0 moles CO2

6 0
3 years ago
Calculate the molarity of a solution of barium hydroxide if 18.15 ml of it is required for the titration of a 20.00 ml sample of
inysia [295]
The balanced equation for the reaction between Ba(OH)₂ and HCl is as follows;
Ba(OH)₂ + 2HCl ---> BaCl₂ + 2H₂O
stoichiometry of Ba(OH)₂ to HCl is 1:2
the number of HCl moles that have reacted - 0.2452 mol/L x (20.00 x 10⁻³ L)
number of HCl moles reacted = 0.004904 mol
2 mol of HCl reacts with 1 mol of Ba(OH)₂
therefore 0.004904 mol of HCl reacts with - 1/2 x 0.004904 mol of Ba(OH)₂
number of Ba(OH)₂ moles in 18.15 mL - 0.002452 mol
Therefore number of Ba(OH)₂ moles in 1000 mL- 0.002452 mol /(18.15 x 10⁻³ L)
molarity of Ba(OH)₂ is = 0.1351 M
6 0
3 years ago
For each of the following pairs of compounds, name one absorption band that could be used to distinguish between them. CH3CH2OH
GrogVix [38]

Answer:

For CH3CH2OH the OH stretch between 3550-3200 cm-1

For CH3CH2NH2 a pair of bands at 3500 and 3400 cm-1 respectively corresponding to the N-H stretch

Explanation:

CH3CH2OH is ethanol. This is a primary alcohol characterized by the by the -OH (hydroxyl) group. A strong broad IR absorption in the 3550 - 3200 cm-1 corresponds to the O-H stretch and indicates that the compound could be an alcohol or it has an OH functional group.

CH3CH2NH2 is ethylamine. This is a primary amine characterized by the -NH2 (amino) group. The presence of a primary amine shows up as a pair of medium strength absorption features corresponding to the N-H stretch, one at around 3500 cm-1 and the other around 3400 cm-1.

7 0
3 years ago
When bsia is assembled as an octamer, what is most likely to be true regarding l76, l77, and l79?
telo118 [61]

The option that is most likely to be true regarding L76, L77, and L79  is that option B: The assembly would incur an entropic penalty if they occupied a solvent-exposed site.

<h3>What is entropic penalty?</h3>

The entropic penalty in regards to ordered water is known to be one that tells or account  for any form of  weaker binding of the antibiotic novobiocin to what we call resistant mutant of DNA gyrase.

Note that in regards to the scenario above, the Entropic penalty is seen as the thermodynamically disfavored needs that is required in forming a cage of polar solvent molecules that is known to be seen around surface that has exposed hydrophobic potion of a molecule.

Hence, The option that is most likely to be true regarding L76, L77, and L79  is that option B: The assembly would incur an entropic penalty if they occupied a solvent-exposed site.

Learn more about octamer from

brainly.com/question/13198179

#SPJ1

See full question below

When Bs1A is assembled as an octamer, what is most likely to be true regarding L76, L77, and L79?

A. They are oriented toward the solvent-exposed exterior of the protein assembly.

B. The assembly would incur an entropic penalty if they occupied a solvent-exposed site.

C. Unlike in a monomer, they are not situated within the hydrophobic cap.

D. Their physiochemical properties are not substantially dependent on their hydrophobicity

5 0
2 years ago
Click on the image that most accurately represents a pure<br> compound.<br> Corre<br> Incor
DochEvi [55]
No image included .
7 0
3 years ago
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