Answer:
Here is your answer
Step-by-step explanation:
B) 2x + 5 = 7
vertical line
C) 2x - y = 6
oblique line
D) 3y + 9 = 0
horizontal line
Answer:
Step-by-step explanation:
r = 8 units
Area = (1/4)πr²

<span>The probability that all three children will be girls is 1/3 because 3 are about to be born</span>
Answer: 2.14 %
Step-by-step explanation:
Given : pH measurements of a chemical solutions have
Mean : 
Standard deviation : 
Let X be the pH reading of a randomly selected customer chemical solution.
We assume pH measurements of this solution have a nearly symmetric/bell-curve distribution (i.e. normal distribution).
The z-score for the normal distribution is given by :-

For x = 6.74

For x = 6.76

The p-value =

In percent, 
Hence, the percent of pH measurements reading below 6.74 OR above 6.76 = 2.14%
I believe it’s option #3. hopefully that helps :)