<h3>Given</h3>
a cuboid with length, width, height dimensions 5, 6, x
<h3>Find</h3>
the value of x that makes the numerical value of the total surface area equal to the numerical value of the volume
<h3>Solution</h3>
The volume is given by
... V = L·W·H = 5·6·x = 30x
The area is given by
... A = 2(L·W + H(L+W)) = 2(5·6 +x(5+6)) = 2(30 +11x) = 60 +22x
When these are equal, we have
... 30x = 60 +22x
... 8x = 60
... x = 7.5
The desired value of x is 7.5.
Multiply it out
x^2 + 4x -8x -32
Combine like terms
x^2 -4x - 32
Draw a number line with 10 positives and 10 negatives. Count from 0 to 8. Now, from 8, count back 12 spots. From that spot, go back to 0, which is their original position. The number you counted there is your answer.
Answer:
Step-by-step explanation:
Multiply by 4
so x+3=8*4
x+3=32
-3. -3
x=29
Angles RZT, RZS, and TZS form triangle RZT, so they sum to 180. Thus, we have:
110+3s+8s=180
Simplifying, we have:
11s=70
Dividing by 11, we see that:
s=70/11
Therefore, RZS=3s=210/11, and TZS=8s=560/11.
