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3 years ago

12

A source of laser light sends rays AB and AC toward two opposite walls of a hall. The light rays strike the walls at points B an

d C, as shown below
What is the distance between the walls?
Answer
50 m
70 m
100 m
110 m

2 answers:

Gekata [30.6K]3 years ago

3 0

Answer:

Your answer would be B. 70 m good sir

Step-by-step explanation:

Vlada [557]3 years ago

3 0

Answer:

70

Step-by-step explanation:

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If you could show as much work as possible that would be amazing!!

Nikitich [7]

Answers:

<u>Reduce:</u>

Here we gave to simplify the expressions:

9) $x^{2}+7x+\frac{12}{x^{2}}+11x+28$

Grouping similar terms:

$(x^{2}+\frac{12}{x^{2}})+(18x+28)$

Applying common factor $x^{2}$ in the first parenthesis and common factor $2$ in the second parenthesis:

$x^{2}(1+\frac{12}{x^{4}})+2(9x+14)$ This is the answer

11) $y^{3}+\frac{27}{y^{2}}+2y-3$

Rearranging the terms:

$(y^{3}+2y)+(\frac{27}{y^{2}}-3)$

Applying common factor $y$ in the first parenthesis and common factor $3$ in the second parenthesis:

$y(y^{2}+2)+3(\frac{9}{y^{2}}-1)$ This is the answer

<u>Multiply:</u>

19) $(\frac{12a^{9}u^{7}}{15 c})(\frac{3c^{4}}{21a^{13 u^{8}}})$

Multiplying both fractions:

$\frac{36 a^{9}u^{7}c^{4}}{315 c a^{13}u^{8}}$

Dividing numerator and denominator by 3 and simplifying:

$\frac{12 c^{3}}{105 c a^{4}u}$ This is the answer

21) $(x-\frac{3}{x}-7)(x^{2}-9x+\frac{35}{x^{2}}-18)$

$(\frac{x^{2}-3-7x}{x})(\frac{x^{4}-9x^{3}+35-18x^{2}}{x^{2}})$

Operating with cross product:

$x^{2} (x^{2}-3-7x) x(x^{4}-9x^{3}+35-18x^{2})$

$x^{9} -9x^{8} -18x^{7}+35x^{5}-7x^{8} +63x^{7}+126x^{6}-245x^{4}-3x^{7}+27x^{6}+54x^{5}-105x^{3}$

Grouping similar terms and factoring:

$x^{9}-2(8x^{8}+21x^{7} )+153x^{6}+89x^{5}-5(49x^{4}+21x^{3})$ This is the answer

<u>Divide:</u>

29) $\frac{\frac{k^{6}}{x^{2}}}{\frac{2k^{4}}{3x^{6}}}$

$\frac{3k^{6}x^{6}}{2x^{2}k^{4}}$

Simplifying:

$\frac{3}{2} k^{2}x^{4}$ This is the answer

33) $\frac{\frac{x+5}{x+1}}{\frac{x^{2}+11x+30}{x^{2}+3x+2}}$

$\frac{(x+5)(x^{2}+3x+2)}{(x+1)(x^{2}+11x+30)}$

Factoring numerator and denominator:

$\frac{(x+5)(x+2)(x+1)}{(x+1)(x+6)(x+5)}$

Simplifying:

$\frac{x+2}{x+6}$ This is the answer

37) $\frac{\frac{x-10}{x+13}}{\frac{x^{3}-1000}{x^{2}+15x+21}}$

$\frac{(x-10)(x^{2}+15x+21)}{(x+13)(x^{3}-1000)}$

Applying the distributive property in numerator and denominator:

$\frac{x^{3}+15x^{2}+21x-10x^{2}-150x-210}{(x+13)(x^{4}-1000x+13x^{3}-13000)}$

Grouping similar terms and factoring by common factor:

$-\frac{5x(x^{2}-129)(x^{2}-42)}{1000x^{3} (x+13)(x-13)}$

Dividing by $5$ in numerator and denominator and simplifying:

$-\frac{(x^{2}-129)(x^{2}-42)}{200x^{2}(x+13)(x-13)}$ This is the answer

3 0

3 years ago

The endpoints of a diameter of a circle are A(3,1) and B(9,9). Find the area of the circle in terms of pie

andrey2020 [161]

Answer:

The answer is $25\pi$ units squared.

Step-by-step explanation:

If we find the diameter, we can find the radius by halving the diameter.

We can find the diameter by using the endpoints of the diameter.

The distance formula will give us the length between (3,1) and (9,9).

The distance formula is $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$ .

The distance between the $x$ 's is 9-3=6.

The distance between the $y$ 's is 9-1=8.

The distance between the points is given by $\sqrt{6^2+8^2}=\sqrt{36+64}=\sqrt{100}=10$ .

The radius is therefore $\frac{10}{2}=5$ .

We are asked to find the area of this circle.

The formula for finding the area of a circle is $\pi r^2$ .

Since the radius is $5$ , then the area in terms of $\pi$ ,(pi), is $\pi (5)^2=\pi (25)$ .

The answer is $25\pi$ units squared.

4 0

3 years ago

Find the Constant Rate of Change of the following table: k =

ValentinkaMS [17]

9514 1404 393

Answer:

10

Step-by-step explanation:

If there is a constant rate of change, its value will be ...

k = y/x

k = 250/25 = 10

The constant rate of change is 10.

y = 10x

8 0

3 years ago

Help me pleseeeeeeeee

Licemer1 [7]

Answer: each number represents the sum of the two numbers

Step-by-step explanation:

I’ve never done this question before but bright to sum of the numbers together

6 0

3 years ago

What is the smallest, positive integer value of x such that the value of f(x) = 2x + 3 exceeds the value of g(x) = 50x + 5?

weeeeeb [17]

F(x) > g(x)
2^x + 3 > 50x + 5

for x = 3 , f(3) > g(3)
11 > 155 (false)

for x = 10 , f(10) > g(10)
1027 > 505 (true)

for x = 9 , f(9) > g(9)
515 > 455 (true)

for x = 8 , f(8) > g(8)
259 > 405 (false)

the smallest,positive integer value of x is 9 since the value of 9 is the last number to exceeds g(x)

7 0

3 years ago