Answer:
28 5 dollar bills
12 10 dollar bills
Step-by-step explanation:
You can write two equations to model this situation'
x will be the number of 5 dollar bills
y will be the number of 10 dollar bills
x+y=40
5x+10y=260
There are a couple of ways you can solve this but but I will be doing it through substitution because that looks easier (I can explain other methods if you're interested)
So we have x+y=40
If I subtract y from both sides and divide by -1 we get
-x+40=y
We can then plug this value in for y in the second equation
5x+10(-x+40)=260
Distribute the 10 and combine like terms to get
-5x+400=260
subtract 400 from both sides and divide by -5 to get
x=28
This means that there are 28 5 dollar bills. We can plug this value back in for x into our first equation to solve for y
28+y=40
Subtract 28 from both sides
y=12
This means that there were a total of 28 5 dollar bills and 12 10s
I doubled checked this in desmos and it checks out
Answer:
wheres the picture?
Step-by-step explanation:
Answer:
The slope is -2
Step-by-step explanation:
To find the slope we do y2 - y1 / x2 - x1 or in this case, -6 - 2 / 9 - 5
Next, u solve -6 - 2 = -8 and 9 - 5 = 4
So we get -8/4 or simplified -2/1 or -2
The slope is -2
Hope that helps u! :)
I'm kind of confused with your question. but I know what will help you you need to subtract
Answer: ![\frac{1}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D)
Step-by-step explanation:
Use the formula for calculate the distance between two points:
![d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B%28x_2-x_1%29%5E2%2B%28y_2-y_1%29%5E2%7D)
Calculate the distance AB. Substitute the coordinates into the formula. Then:
![d_{AB}=\sqrt{(8-0)^2+(8-(-7))^2}](https://tex.z-dn.net/?f=d_%7BAB%7D%3D%5Csqrt%7B%288-0%29%5E2%2B%288-%28-7%29%29%5E2%7D)
![d_{AB}=17](https://tex.z-dn.net/?f=d_%7BAB%7D%3D17)
Calculate the distance A'B'. Substitute the coordinates into the formula. Then:
![d_{A'B'}=\sqrt{(2-6)^2+(1-5-(-6))^2}](https://tex.z-dn.net/?f=d_%7BA%27B%27%7D%3D%5Csqrt%7B%282-6%29%5E2%2B%281-5-%28-6%29%29%5E2%7D)
![d_{A'B'}=\frac{17}{2}](https://tex.z-dn.net/?f=d_%7BA%27B%27%7D%3D%5Cfrac%7B17%7D%7B2%7D)
As you can see, the distance A'B' is the distance AB multiplied by 1/2. Therefore, this is the scale factor.