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Licemer1 [7]
3 years ago
13

PLEASE HELP!!!! I'll mark Brainliest for whoever is first!!!!

Computers and Technology
2 answers:
Otrada [13]3 years ago
7 0

Answer:

It counts the number of birds in the list.

larisa86 [58]3 years ago
7 0

Answer:

It counts the number of birds in the list.

Explanation:

You might be interested in
Let A and B be two stations attempting to transmit on an Ethernet. Each has a steady queue of frames ready to send; A’s frames w
Mariana [72]

Answer:

Following are the solution to the given question:

Explanation:

Please find the complete and correct question in the attachment file.  

For Point a:

For the second round,

A is selects kA(2)  either 0 or 1, so for each of them, that is \frac{1}{2}.

B selects kB(2)\  from\  (0, 1, 2, 3) for each choice with the probability of \frac{1}{4}.

If kA(2) < kB(2) wins the second rear race.

\to P[A \ wins] = P[kA(2) < kB(2)]

                     = P[kA(2) = 0] \times P[kB(2) > 0] + P[kA(2) = 1] \times P[kB(2) > 1]\\\\= \frac{1}{2} \times \frac{3}{4}  + \frac{1}{2}  \times \frac{2}{4} \\\\=\frac{3}{8}  +\frac{2}{8} \\\\= \frac{3+2}{8}\\\\= \frac{5}{8}

For Point b:

Throughout this example, kA(3) also selects to be either 0 or 1 with such a \frac{1}{2} probability. So, although B chooses kB(3) from (0, 1, 2, 3, 4, 5, 6, 7), the probabilities each are \frac{1}{8}:

\to P[A \  wins] = P[kA(3) < kB(3)]

                     = P[kA(3) = 0] \times P[kB(3) > 0] + P[kA(3) = 1] \times P[kB(3) > 1]\\\\= \frac{1}{2} \times \frac{7}{8} + \frac{1}{2} \times \frac{6}{8}\\\\= \frac{7}{16} + \frac{6}{16}\\\\= \frac{7+6}{16} \\\\= \frac{13}{16}\\\\

For point c:

Assume that B tries again 16 times (typical value), and it destroys. In addition, throughout the exponential background n is obtained at 10 when choosing k between 0 to 2n−1. The probability of A winning all 13 backoff events is: P[A \text{wins remaining races}] = 16\pi i =4P[A \ wins \ i |A \ wins \ i -1 ]

Let the k value kA(i) be A for the backoff race I select. Because A retains the breed

=(kA(i)] \cdot P[kA(i+ 1)< kB(i+ 1)] \geq P[kA(i) + 1

For point d:

Two stations A and B are supposed. They assume that B will try 16 times afterward. Even so, for A, 16 races were likely to also be won at a rate of 0.82 For Just higher expectations of three A, B, and C stations. For Station A, possibility to win all backoffs

3 0
3 years ago
Which is a good way to improve your credit score
labwork [276]
Pay your bills and don't be late
8 0
4 years ago
Write a program that converts a number entered in Roman numerals to decimal.
Montano1993 [528]

Answer:

Here is the JAVA program:

import java.util.Scanner;   // for importing scanner class

public class RomanToDecimal{  //class to convert roman numeral to decimal

       static String romNum;  // variable that stores roman numeral

       static int decNum;  //variable that stores decimal number

       public static void main(String args[]) {  //start of the program

              //romtodec object created

              RomanToDecimal romtodec = new RomanToDecimal();  

//call function decimalConversion() that converts roman numeral to decimal

              romtodec. decimalConversion();  

//call function displayRomanNumeral to display the results of conversion

               romtodec. displayRomanNumeral(romNum);

//call function to display the decimal no. of roman numeral

               romtodec . displayDecimalNumber(decNum);   }

//method decimalConversion to convert Roman numeral to decimal

     public void decimalConversion () {

     Scanner scan = new Scanner(System.in);  //to get input

       //prompts user to enter a Roman numeral

     System.out.print("enter a Roman numeral: ");

               romNum = scan.nextLine();  //reads input    

               //stores the length of the entered Roman numeral                                            

                int length=  romNum.length();  

               int number=0;  //initializes number to 0

               int prevNum = 0;  //initializes previous number to 0

          //loops through the length of the input Roman numeral

               for (int i=length-1;i>=0;i--)  

//charAt() method returns the roman numeral symbol at the index i

               { char symbol =  romNum.charAt(i);

       //every symbol will be converted to upper case

                       symbol = Character.toUpperCase(symbol);

//switch statement tests the symbol variable for equality against a list of //numerals given and each numeral is assigned its equal decimal value.

                         switch(symbol)

                       {   case 'I':

                               prevNum = number;

                               number = 1;

                               break;

                            case 'V':

                                    prevNum = number;

                               number = 5;

                               break;

                               case 'X':

                                       prevNum = number;

                               number = 10;

                                break;

                               case 'L':

                                       prevNum = number;

                               number = 50;

                               break;

                               case 'C':

                                        prevNum = number;

                               number = 100;

                               break;

                               case 'D':

                                        prevNum = number;

                               number = 500;

                               break;

                               case 'M':

                                        prevNum = number;

                               number = 1000;

                               break; }          

/*checks if the number is greater than previous number

if the value of current roman symbol (character) is greater than the next

symbol's value. then add value of current roman symbol to the decNum

else subtract the value of current roman symbol from the value of its next symbol. */              

                       if (number>prevNum)

                           { decNum= decNum+number;  }

                       else

                          decNum= decNum-number;  }

//displays the decimal value of the roman numeral

       public static void displayRomanNumeral (String romNum){

               System.out.println ("The Roman numeral "+romNum+" is equal to decimal number"+decNum); }

//displays the number as decimal

           public static void displayDecimalNumber (int decNum){

       System.out.println ("The decimal number is: " + decNum);  } }      

Output:

enter a Roman numeral: MCXIV

The Roman numeral MCXIV is equal to decimal number 1114

Output:

enter a Roman numeral: CCCLIX

The Roman numeral CCCLIX is equal to decimal number 359

Output:

enter a Roman numeral: MDCLXVI

The Roman numeral MDCLXVI is equal to decimal number 1666

5 0
4 years ago
Put the following steps of the problem solving process in correct order.
Goryan [66]
It is already in a correct order
3 0
3 years ago
In the formula =SUM(A6:A9), which of the following best describes A6:A9
lianna [129]

Arguments are indeed the values used by <em>functions to perform computations</em>, and the further discussion can be defined as follows:

  • <em>Functions</em> in spreadsheet programs including Excel Sheets are simply built-in formulas that perform predefined calculations.
  • In this, the majority of these functions require data to be supplied, either by the user or from another source, to deliver a result.
  • It is a real value that is provided to the function, as well as the parameters, are initialized to the value of the arguments supplied.
  • In this question, a method "SUM(A6:A9)" is declared that takes value from A6 to A9, in its parameter(Argument) that <em>adds value from</em>.  

Therefore, the final answer is "Option A".

Learn more:

brainly.com/question/12269471

6 0
3 years ago
Read 2 more answers
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