The a is idshdvsvehdhdbdhdhggansnsbfsbshd
Answer:
The first one
Step-by-step explanation:
Let <em>V</em> be the volume of the tank. The inlet pipe fills the tank at a rate of
<em>V</em> / (5 hours) = 0.2<em>V</em> / hour
and the outlet pipe drains it at a rate of
<em>V</em> / (8 hours) = 0.125<em>V</em> / hour
With both valves open, the net rate of water entering the tank is
(0.2<em>V</em> - 0.125<em>V </em>) / hour = 0.075<em>V</em> / hour
If <em>t</em> is the time it takes for the tank to be full, then
(0.075<em>V</em> ) / hour • <em>t</em> = <em>V</em>
Solve for <em>t</em> :
<em>t</em> = <em>V</em> / ((0.075<em>V</em> ) / hour)
<em>t</em> = 1/0.075 hour
<em>t</em> ≈ 13.333 hours
It is shown that by looking at the formula for the volume of a cylinder (we assume that the trash can is cylindrical):
V = pi*r^2*h
We can conclude that the volume of the trash can is directly proportional to its radius and height. To wrap up, the volume would increase as the radius of the trash can's base, and its height would be increased as well.