The perimeter of these can be found by adding length and width and then multiplying by two.
Rectangle A: (with all of the variables already doubled)
2x + 16 + 2x - 2
2x + 2x + 16 - 2
4x + 14
So rectangle A's perimeter is 4x + 14.
Rectangle B: (Still with all the variables already doubled)
8x + 10 + 6x - 4
8x + 6x + 10 - 4
14x + 6
So rectangle B's perimeter is 14x + 6
And now to subtract the two.
(7x + 3) - (4x + 14)
14x + 6 - 4x - 14
14x - 4x + 6 - 14
10x - 8
So it would be C.
Answer:
B is the answer because yes
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Surface area of the cube
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6(2.5 x 2.5) = 37.5m²
<em>(* Each area is 2.5 x 2.5, and there are 6 sides to the cube)</em>
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Surface area of the rectangle prism
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2(11 x 7) + 2(9 x 7) + 2(9 x 11) = 478m²
<em>(* The opposite side of the rectangle area is the same, therefore x2)
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Overlapping area
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2.5 x 2.5 = 6.25m²
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Surface area of the composite figure
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37.5 + 478 - 2(6.25) = 503m²
<em>(* The bottom of the cube and the top of the rectangle prism overlapped, so the area is overlapped twice, minus 2 times of that area)</em>
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Answer: 503m²
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The answer is 62^ it reflects angle IK
Answer:
The measure of the longer base is:
9 centimeters
Step-by-step explanation:
We know that the area of a trapezoid with height h and two parallel bases b and b' is given by the formula:
Here we have:
The area of a trapezoid is 30 square centimeters. The height is 4 centimeters. The shorter base measures 6 centimeters.
i.e.
Step-by-step explanation:
