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3 years ago

PLSSSS ANSWER!!!!

Mathematics

2 answers:

Elena-2011 [213]3 years ago

8 0

The answer is y=1/2x-2. I really recommend you to get yourself a TI-84 calculator. It will help you with problems like these.

patriot [66]3 years ago

6 0

The answer is y=1/2x-2

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Andre says 10x + 6 and 5x + 11 are equivalent because they both equal 16 when x is 1. Do you agree with Andre?

Serga [27]

Answer:

No, They are not equivalent

Step-by-step explanation:

The two expressions are only said to be equivalent if they are the same regardless of whatever value the variable(s) is.

The variable in this question is x.

To prove this, we equate both expressions:

$10x + 6 = 5x + 11$

$10x - 5x = 11 - 6\\\\\\5x = 5\\\\\\x = 1$

This shows that they have the same value ONLY when x is 1.

This is why Andre says that they are equivalent, but they are not.

8 0

3 years ago

If sin Ѳ = cos 40, find the value Ѳ

Jet001 [13]

Answer:

Θ = 50°

Step-by-step explanation:

Using the cofunction identity

cosx = sin(90 - x)

Given

cos40° = sin(90 - 40)° = sin50° ⇒ Θ = 50°

7 0

3 years ago

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The attendant at a parking lot compared the number of hybrid vehicles to the total number of vehicles in the lot over a weekend.

babymother [125]

5 Aii that answer is 5

8 0

3 years ago

-4 (9x-2) simplify expression using distributive property

Scorpion4ik [409]

(-4) (9x) + (-4) (-2)
-36x + 8

6 0

3 years ago

In simplest radical form, what are the solutions to the quadratic equation 0 = –3x2 – 4x + 5? Quadratic formula: x = StartFracti

weqwewe [10]

The solutions of the quadratic equation 0 = -3x² - 4x + 5 are

$x=\frac{-2-\sqrt{19}}{3}$ and $x=\frac{-2+\sqrt{19}}{3}$

Step-by-step explanation:

The quadratic formula of the quadratic equation ax² + bx + c = 0, is

$x=\frac{-b+-\sqrt{b^{2}-4ac}}{2a}$

To find the solution of the quadratic equation by using quadratic formula

Find the values of a, b, and c from the quadratic equation
Substitute these values in the quadratic formula
Calculate the values of x

∵ -3x² - 4x + 5 = 0

∴ a = -3 , b = -4 and c = 5

- Substitute these values in the quadratic formula

∵ $x=\frac{-(-4)+\sqrt{(-4)^{2}-4(-3)(5)}}{2(-3)}$

∴ $x=\frac{4+\sqrt{16+60}}{-6}$

∴ $x=\frac{4+2\sqrt{19}}{-6}$

- Simplify by dividing up and down by -2

∴ $x=\frac{-2-\sqrt{19}}{3}$

∵ $x=\frac{-(-4)-\sqrt{(-4)^{2}-4(-3)(5)}}{2(-3)}$

∴ $x=\frac{4-\sqrt{16+60}}{-6}$

∴ $x=\frac{4-2\sqrt{19}}{-6}$

- Simplify by dividing up and down by -2

∴ $x=\frac{-2+\sqrt{19}}{3}$

The solutions of the quadratic equation 0 = -3x² - 4x + 5 are

$x=\frac{-2-\sqrt{19}}{3}$ and $x=\frac{-2+\sqrt{19}}{3}$

Learn more:

You can learn more about quadratic equation in brainly.com/question/7361044

#LearnwithBrainly

9 0

3 years ago

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