The equivalent of film speed in a digital camera is going to be sensitivity. This will make the correct answer B.
Answer:
#include <iostream>
using namespace std;
int main()
{
int i = 45;
for ( i = 45; i <=165; i = i + 6)
cout << i << endl;
}
Explanation:
I corrected your code and highlighted the mistakes. Even though you wrote the correct algorithm, your code did not compile because of the typos you made.
Remember, C++ is a case-sensitive language. That means, "For" is not same as "for".
Generally, variables and keywords are written in lower case. Of course, there are exceptions, such as constant variables are all written in uppercase letter and class names start with an uppercase letter.
B. all of those.
just to clarify,
HDMI is the port for monitor and sound.
VGA is for video/monitor port
and display port.... I don't know, but it's a type of monitor port.
Go into your trash bin in your computer.
Answer:
words.hasNext()
Explanation:
Given the code snippet below:
- while (inputFile.hasNextLine()) {
- String word = "";
- String line = inputFile.nextLine();
- Scanner words = new Scanner(line);
- while (words.hasNext()) {
- word = words.next();
- }
- System.out.println(word); }
- }
We have a inputFile Scanner object that can read data from a text file and we presume the inputFile has read several rows of data from the text file. So long as there is another line of input data available, the outer while loop will keep running. In each outer loop, one line of data will be read and assign to line variable (Line 3). Next, there is another Scanner object, words, which will take the current line of data as input. To get the last word of that line, we can use hasNext() method. This method will always return true if there is another tokens in its input. So the inner while loop will keep running so long as there is a token in current line of data and assign the current token to word variable. The word will hold the last token of current line of data upon exit from the inner loop. Then we can print the output (Line 8) which is the last word of the current line of data.
