Answer:
QR=8
QU=76
Measure of arc ST=114°
Measure of arc QR=114°
Measure of arc XT=57°
Step-by-step explanation:
Given
YU=YV
ST=16
mQS=34
mRT=98
Using Pythagoras theorem,
QR=8
QU=76
QR=ST
So they both span the same arc.
Let the arc=x
360 - QS - RT = QR + ST
Recall QR=ST
360 - 34 - 98 = x + x
228 = 2x
X=228/2
X=114°
Therefore, measure of arc ST and arc QR=114° each
Measure of the span of arc XT = (1/2) of (arc ST)
= (1/2)(114°)
= 57°
X-2y-3=0 should be the answe
3(2x+1)=2(x+1)+1
Step 1:Simplify both sides of the equation
(3)(2x)+(3)(1)=(2)(x)+(2)(1)+ -(distribute)
6x+3=2x+2+1
6x+3=(2x)+(2+1) -(Combine Like Terms)
6x+3=2x+3
Step 2: Subtract 2x from both sides
6x+3-2x=2x+3-2x
4x+3-3=3-3
4x÷4=0÷4
x=0
The first one:
5v + 3 = 5v - 5
Subtract 5v from both sides ->
3 = -5
This isn't true so that means there are no solutions...
